If SE开发者_开发问答LECT SUM(amount) FROM transactions ORDER BY order LIMIT 0, 50
sums the amount
field for the first 50 records in a table, how do a sum all records after the first 50? In other words, I'd like to do something like SELECT SUM(amount) from transactions ORDER BY order LIMIT 50, *
, but that doesn't work.
SELECT SUM(amount)
FROM (
SELECT amount
FROM transactions
ORDER BY
order
LIMIT 50, 1000000000000
) q
Note that your original query:
SELECT SUM(amount)
FROM transactions
ORDER BY
order
LIMIT 0, 50
does not do what you probably think it does. It is synonymous to this:
SELECT a_sum, order
FROM (
SELECT SUM(amount) AS a_sum, order
FROM transactions
) q
ORDER BY
order
LIMIT 0, 50
The inner query (which would normally fail in any other engine but works in MySQL
due to its GROUP BY
extension syntax) returns only 1
records.
ORDER BY
and LIMIT
are then applied to that one aggregated record, not to the records of transactions
.
The documentation advices to use an incredible large number as second parameter to LIMIT
:
To retrieve all rows from a certain offset up to the end of the result set, you can use some large number for the second parameter. This statement retrieves all rows from the 96th row to the last:
SELECT * FROM tbl LIMIT 95,18446744073709551615;
There is probably a more efficient way, but you could run a count query first, to retrieve total # of rows in your table:
SELECT count(*) FROM transactions
Stuff that into a variable and use that variable as your second argument for LIMIT. You could probably do this as a nested mysql query.
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