What does this python line mean?

abc = [0, ] * datalen;

"datalen" is an Integer.开发者_如何学JAVA

Then I see referencing like this:

abc[-1]

Any ideas?

---

creates a list with datalen references to the object 0:

>>> datalen = 10
>>> print [0,] * datalen
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

You don't really need the comma in there:

>>> print [0] * datalen
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]

---

As everyone else has said, [0] * n will give you a list of n zeros, and indexing with negative numbers with a[-k] gives k-th element from the end, like:

a[-1]

gives the last element of the sequence and

a[-3]

gives the third last element of the sequence.

---

In addition to what has been said, remember that this behavior is expected when you are copying mutable objects. Classic trap for new python programmers

>>> bc = [0,] * 5
>>> bc
[0, 0, 0, 0, 0]
>>> bc[2]=4
>>> bc
[0, 0, 4, 0, 0]


>>> bb = [{}, ]*5
>>> bb
[{}, {}, {}, {}, {}]
>>> bb[2]["hello"]="hi"
>>> bb
[{'hello': 'hi'}, {'hello': 'hi'}, {'hello': 'hi'}, {'hello': 'hi'}, {'hello': 'hi'}]
>>> 

---

When used in this context, * is the "sequence repetition" operator.

>>> datalen = 3
>>> abc = [0,] * datalen
[0, 0, 0]

In this case, it looks like it's being used as a way to create an array with datalen elements, all of which are initialized to zero.

This works for strings too (since they are also sequences):

>>> 'String' * 3
'StringStringString'

---

creates a list with datalen number of zeroes

>>> datalen=5
>>> abc = [0, ] * datalen
>>> abc
[0, 0, 0, 0, 0]