开发者

Function with missing return value, behavior at runtime

开发者 https://www.devze.com 2022-12-26 06:12 出处:网络
As expected, the compiler (VisualStudio 2008) will give a warning warning C4715: \'doSomethingWith\' : not

As expected, the compiler (VisualStudio 2008) will give a warning

warning C4715: 'doSomethingWith' : not all control paths return a value

when compiling the following code:

int doSomethingWith(int value)
{
    int returnValue = 3;
    bool condition = false;

    if(condition)
        // returnValue += value; // DOH

    return returnValue;
}

int main(int argc, char* argv[])
{
    int foo = 10;
    int result = doSomethingWi开发者_开发技巧th(foo);
    return 0;
}

But the program runs just fine. The return value of function doSomethingWith() is 0.

Is is just undefined behavior, or is there a certain rule how the result value is created/computed at runtime. What happens with non-POD datatypes as return value?


It is Undefined behaviour as specified in the ISO C++ standard section 6.6.3:

Flowing off the end of a function is equivalent to a return with no value; this results in undefined behavior in a value-returning function.


For x86 processors, the standard calling convention puts the return value to the EAX register. Practically it means that for most compilers if we reach the end of the function without returning, the result of the last math operation will be returned. However, you can not rely on it and it is not portable.

http://en.wikipedia.org/wiki/X86_calling_conventions#cdecl


Updating @piotr answer.

From the C++17 Standard Section 9.6.3

Flowing off the end of a constructor, a destructor, or a function with a cv void return type is equivalent to a return with no operand. Otherwise, flowing off the end of a function other than main (6.6.1) results in undefined behavior.


Not returning a value from a value-returning function leads to undefined behavior.

0

精彩评论

暂无评论...
验证码 换一张
取 消