I'm writing an algorithm that iterates over a list of points, calculate开发者_如何学Pythons the distance between them and inserts additional points if the distance is too great. However I seem to be lacking the proper familiarity with STL to come up with an elegant solution. I'm hoping that I can learn something, so I'll just show you my code. You might have some hints for me.
for (std::list<PathPoint>::iterator it = ++points_.begin();
it != points_.end(); it++)
{
Vector curPos = it->getPosition();
Vector prevPos = (--it)->getPosition();
Vector vecFromPrev = curPos - prevPos;
float distance = vecFromPrev.abs();
it++;
if (distance > MAX_DISTANCE_BETWEEN_POINTS)
{
int pointsToInsert = (int)(distance / MAX_DISTANCE_BETWEEN_POINTS);
Vector curPos = prevPos;
for (int i = 0; i < pointsToInsert; i++)
{
curPos += vecFromPrev / pointsToInsert;
it = points_.insert(it, PathPoint(curPos, false));
it++;
}
}
}
Consider using adjacent_find
to find an iterator position where the distance between consecutive elements is too large, then inserting pointsToInsert
items.
http://www.sgi.com/tech/stl/adjacent_find.html
In addition, you could use generate
with a functor to fill in the intermediate points.
http://www.sgi.com/tech/stl/generate.html
Not sure how deep you want to go into STL :)
You're iterative solution is perfectly understandable. I know when you say "I'm hoping that I can learn something" this is not what you intended, but what I hope you learn is:
1) There is no benefit to finding an "elegant" functional solution to a problem you have solved iteratively in a fine way
2) Functional programming in C++ is tedious, even more so than C++ is already tedious.
I don't like mentioning the iterator types because 1.) they're kind of ugly and 2.) it reduces the changes I have to make if I change collection types, so I would probably do something like this....
I made a couple additional tweaks that are probably more my personal style than idiomatic.
this->addAdditionalPoints(points.begin(), points.end());
template<typename InIt>
void MyClass::addAdditionalPoints(InIt start, InIt finish)
{
InIt it = start;
++it; // Starting with second element
for (; it != finish; ++it) // I usually pre-increment iterators, but
// it probably doesn't matter.
{
InIt curr = it; // Work with a temp rather than loop index
Vector curPos = curr->getPosition();
Vector prevPos = (--curr)->getPosition();
Vector vecFromPrev = curPos - prevPos;
float distance = vecFromPrev.abs();
++curr; // Prefer to pre-increment iterators
if (distance > MAX_DISTANCE_BETWEEN_POINTS)
{
int pointsToInsert = static_cast<int>(distance /
MAX_DISTANCE_BETWEEN_POINTS); // I prefer C++-style casts
Vector curPos = prevPos;
for (int i = 0; i < pointsToInsert; i++)
{
curPos += vecFromPrev / pointsToInsert;
curr = points_.insert(curr, PathPoint(curPos, false));
++curr; // Again I prefer to pre-increment iterators
}
}
}
}
You don't have to catch the return value of the list insert to the iterator. That way, you don't need to manually increment it.
for (int i = 0; i < pointsToInsert; i++)
{
curPos += vecFromPrev / pointsToInsert;
points_.insert(it, PathPoint(curPos, false));
}
Stephen's solution is a good one, but in the interest of education, you can loop over two variables at once:
typedef typename std::list<PathPoint>::iterator Itr; //Pointless, but just to illustrate the possibility
for(Itr cur = points_.begin(), prev = cur++; cur != points_.end(); ++prev, ++cur) {
Vector curPos = cur->getPosition();
Vector prevPos = prev->getPosition();
Vector vecFromPrev = curPos - prevPos;
float distance = vecFromPrev.abs();
if (distance > MAX_DISTANCE_BETWEEN_POINTS) {
int pointsToInsert = (int)(distance / MAX_DISTANCE_BETWEEN_POINTS);
Vector curPos = prevPos;
for (int i = 0; i < pointsToInsert; i++) {
curPos += vecFromPrev / pointsToInsert;
prev = points_.insert(cur, PathPoint(curPos, false));
//as somebody mentioned, `cur` remains valid during `list` insertions
}
}
}
Moving your iterator back and forth like that is somewhat confusing. Also, note that neither this, nor your original code, like empty lists very much.
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