Converting PHP pagination to jQuery?

Hey, I have been trying to get this pagination class that I am using to be more ajaxy - meaning when I click on the page number like page [2] the data loads, but I want to load in the data without going to a different page (HTTP request in the background, with no page reloads).

Being new to both php and jquery, I am a little unsure on how to achiev开发者_StackOverflowe this result, especially while using a php class.

This is what the main page looks like by the way:

<?php
$categoryId=$_GET['category'];
echo $categoryId;
?>

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script>
<script type="text/javascript" src="jquery_page.js"></script>

<?php
    //Include the PS_Pagination class
    include('ps_pagination.php');
    //Connect to mysql db
    $conn = mysql_connect('localhost', 'root', 'root');
    mysql_select_db('ajax_demo',$conn);
    $sql = "select * from explore where category='$categoryId'";
    //Create a PS_Pagination object
    $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2');
    //The paginate() function returns a mysql
    //result set for the current page
    $rs = $pager->paginate();
    //Loop through the result set

echo "<table width='800px'>";

    while($row = mysql_fetch_assoc($rs)) {            

                echo "<tr>";
                    echo"<td>";
                        echo $row['id'];
                    echo"</td>";

                    echo"<td>";
                        echo $row['site_description'];
                    echo"</td>";

                    echo"<td>";
                        echo $row['site_price'];
                    echo"</td>";
                echo "</tr>";

    }
echo "</table>";

        echo "<ul id='pagination'>";

            echo "<li>";
            //Display the navigation
            echo $pager->renderFullNav();
            echo "</li>";

        echo "</ul>";

?>

<div id="loading" ></div>
<div id="content" ></div>

Would I need to do something with this part of the class?, as seen above:

$pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2');

Or this?:

echo $pager->renderFullNav();

I don't no much about jquery,but i guess I would start it like:

$("#pagination li").click(function() {

Then load something maybe...

I don't no. Any help on this would be great. Thanks.

---

Im not sure how to go about it using that class, it seems it would be a bit tricky, as the script you make the ajax call to, to retrieve the data, will need to have access to the current PS_pagination instance.

Without the class though, it wouldnt be too tricky.

You would need a php script to actually return the data, which takes in the number of records per page, and the current page number. In this script, rather than returning the data, i return the html. So i take the data from the database, then generate the table. This means that all i have to do on success of ajax is replace what is in the able currently, with the new html that i get from this script. Heres an example..

//Current Page Number 
$page_num = isset($_GET['page_number']) ?  mysql_real_escape_string($_GET['page_number']) : 1;

//Number of records to show on each page 
$num_records = isset($_GET['num_records_pp']) ?  mysql_real_escape_string($_GET['num_records_pp']) : 10;

//Row to start collecting data from 
$start_row = $num_records * ($page_num - 1);

//String to store html to return 
$return_html = '';

//SQL Query 
$sql = mysql_query("SELECT * FROM my_table LIMIT $start_row, $num_records");

//Query success 
if($sql) {      
    //Construct html for table  
    $return_html = "<table width='800px'>";         

    while($row = mysql_fetch_array($sql)    {       

      $return_html .= "<tr>";       
      $return_html .= "<td>" . $row['id'] . "</td>";        
      $return_html .= "<td>" . $row['site_description'] . "</td>";
      $return_html .= "<td>" . $row['site_price'] . "</td>"; 
      $return_html .= "</tr>";

    }       
    $return_html .= "</table>";

//Query Failed 
} else {

    $return_html = "<p class='error'>Error Fetching Data</p>";

}

return $return_html;

Then you just make a get request via ajax and pass the page number, and the number of rows you want.

$.get("get_data.php", { page_number: 1, num_records_pp: 20 },
   function(data){
     $('div#my_table').html(data);
   });

So, this query assumses that you have a div with an id of "my_table" which contains your table, it will then replace this with a new table consistion of just the data you requested.

This code was just to give you the jist, so i may have some errors in there, but hope it helps.