Getting a partial path to a file in a bash script

I ha开发者_Go百科ve a path that is stored in a variable

$FULLPATH="/this/is/the/path/to/my/file.txt"

I also have another variable containing a partial path

$PARTIAL="/this/is/the/"

I want to remove the partial path from the full path so that I am left with:

path/to/my/file.txt

What's the best way to do this?

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Use bash's # pattern matching operator:

${FULLPATH#${PARTIAL}}

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Here's a little more detail to Mr. Klatchko's excellent answer:

$ FULLPATH="/this/is/the/path/to/my/file.txt"
$ PARTIAL="/this/is/the/"
$ echo ${FULLPATH#${PARTIAL}}
path/to/my/file.txt

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If you're sure that $PARTIAL is an actual path:

result="${FULLPATH#$PARTIAL}"
result="${result#/}"

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# echo $FULLPATH | sed 's#'"$PARTIAL"'##'