Eg
:a=[["hello", "world"], ["good", "lord"], ["hello", "lord"]]
I need to find and record the indexes of each word with respect to the super-array. i.e
hello =&g开发者_Go百科t; 0,2
world => 0
lord => 1,2.
here's my shot ,but its very amateurish and lengthy.
all_tokens=tokens.flatten
all_tokens.each do|keyword|
tokens.each do|token_array|
if token_array.include?keyword
x << i
end
i=i+1
end
y[k] = x.clone
y=y.clear
end
Slight improvement (imho) on vava's solution:
tokens = [["hello", "world"], ["good", "lord"], ["hello", "lord"]]
tokens_hash = Hash.new{|h, k| h[k] = []}
tokens.each_with_index do |subarr, i|
subarr.each do |word|
tokens_hash[word] << i
end
end
ret = []
a.each_with_index {|x, i| if x.include?(keyword) then ret << i end }
a.each_with_index.inject({}){|acc,(elem,i)|
elem.each{|e|
acc[e] ||= []
acc[e] << i
}
acc
}
#=> {"hello"=>[0, 2], "world"=>[0], "good"=>[1], "lord"=>[1, 2]}
tokens = [["hello", "world"], ["good", "lord"], ["hello", "lord"]]
tokens_hash = Hash.new([])
tokens.each_with_index do |subarr, i|
subarr.each do |word|
tokens_hash[word] = tokens_hash[word] + [i]
end
end
p tokens_hash #=>{"good"=>[1], "world"=>[0], "lord"=>[1, 2], "hello"=>[0, 2]}
My solution will scan the whole structure just once.
Just for grins, a functional solution:
#!/usr/bin/ruby1.8
a = [["hello", "world"], ["good", "lord"], ["hello", "lord"]]
b = a.flatten.uniq.inject({}) do |hash, word|
hash.merge(word => a.each_with_index.collect do |list, i|
list.index(word) && i
end.compact)
end
p b # => {"world"=>[0], "good"=>[1], "lord"=>[1, 2], "hello"=>[0, 2]}
a=[["hello", "world"], ["good", "lord"], ["hello", "lord"]]
result = Hash.new{|k,v| k[v] = []}
a.each_with_index{|b,i| b.each{|c| result[c] << i} }
result
#=> {"good"=>[1], "world"=>[0], "lord"=>[1, 2], "hello"=>[0, 2]}
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