A = imread(filename, fmt)
[X, map] = imread(...)
The above is in the synopsis part of imread
, which seems to say that the return value of a MATLAB 开发者_StackOverflowfunction depends on how it's called? Is that true?
IMREAD function is defined as
function [X, map, alpha] = imread(varargin)
In your 2 examples A and X will be the same, but in the second case there will be additional variable map
.
There is a way in MATLAB to define variable output if you use VARARGOUT in function definition:
function varargout = foo(x)
So you can output different values based on some condition in the function body.
This is a silly example, but it illustrates the consept:
function varargout = foo(a,b)
if a>b
varargout{1} = a+b;
varargout{2} = a-b;
else
varargout{1} = a;
varargout{2} = b;
end
Then
[x,y] = foo(2,3)
x =
2
y =
3
[x,y] = foo(3,2)
x =
5
y =
1
The output arguments can be even different data types.
Another example with condition based on number of output variables:
function varargout = foo(a,b)
if nargout < 2
varargout{1} = a+b;
else
varargout{1} = a;
varargout{2} = b;
end
Then
[x,y] = foo(2,3)
x =
2
y =
3
x = foo(2,3)
x =
5
Yes, matlab has a mechanism to provide variable amount results, and also for the input parameters.
You can use it yourself when you write functions, see the documentation about narg* on Mathwork to learn more.
Take for example the histogram function
> hist(1:100); % generates a plot with the 10 bins
> hist(1:100, 4); % generates a plot with 4 bins
> fillrate = hist(1:100, 4); % returns the fill rate for the 4 bins
> [fillrate, center] = hist(1:100,4); % returns the fill rate and the bins center in 2 differen variables
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