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How to execute Imagemagick in PHP

开发者 https://www.devze.com 2022-12-25 14:04 出处:网络
I found a very helpful post on here about cropping images in a circle. However, when I try to execute the imagemagick script using exec in PHP, I\'m getting no results. I\'ve checked to make sure the

I found a very helpful post on here about cropping images in a circle. However, when I try to execute the imagemagick script using exec in PHP, I'm getting no results. I've checked to make sure the directories have the correct permissions and such. Is there a step I'm missing?

Any insight would be much appreciated. Here's what my script looks like:

$run = exec('convert -size 200x200 xc:none -fil开发者_开发知识库l daisy.jpg -draw "circle 100,100 100,1" uploads/new.png');

Edit: Imagemagick is installed.


$out=array();
$err = 0;
$run = exec('convert -size 200x200 xc:none -fill daisy.jpg -draw "circle 100,100 100,1" uploads/new.png',$out,$err);
echo implode ("<br>",$out);
print_r($err);
print_r($run);

what would it say?

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