How do I return the entire set / array using NSPredicate?

I'm building a carArray and want to filter the contents conditionally, using an NSPredicate, like so:

NSPredicate *pred;
switch (carType) {
  case FreeCar:
    pred = [NSPredicate predicateWithFormat:@"premium = NO"];
    break;
  case PremiumCar:
    pred = [NSPredicate predicateWithFormat:@"premium = YES"];
    break;
  default:
    pred = [NSPredicate predicateWithFormat:@"SOME PREDICATE THAT RETURNS EVERYTHING"];
    break;
}
self.carArray = [开发者_如何学JAVAaCarArrayIGotFromSomewhere filteredArrayUsingPredicate:pred];

My question is, what is the correct syntax for the value I've stubbed in as SOME PREDICATE THAT RETURNS EVERYTHING which returns all of the instances in the array / set?

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To return all of the contents a given array / set:

Swift:

NSPredicate(value: true)

for example:

let array : NSArray = ["a", "b", "c", "d", "e"] let predicate = NSPredicate(value: true) array.filteredArrayUsingPredicate(predicate)

yields:

["a", "b", "c", "d", "e"]

To exclude all of the contents a given array / set:

Swift:

NSPredicate(value: false)

for example:

let array : NSArray = ["a", "b", "c", "d", "e"] let predicate = NSPredicate(value: false) array.filteredArrayUsingPredicate(predicate)

yields:

[]

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For always true or always false you can use [NSPredicate predicateWithValue:YES] or [NSPredicate predicateWithValue:NO].