Way to call super(MyClass, self).__init__() without MyClass?

I find this syntax astoundingly annoying. Every time I rename my class, I have to change this call for no apparent reason. Isn't there some __c开发者_Python百科lass__ magic variable or something I can use at least? Interested in answers for Python 2.5, but it doesn't hurt to know if later versions fixed this.

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As far as I know, this isn't possible in 2.5. However, in 3.0, this was changed so that you can simply call super().__init__().

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This is fixed in Python 3. http://docs.python.org/py3k/library/functions.html#super

http://www.python.org/dev/peps/pep-3135/

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If your class only inherits from one class it is safe to do just this:

class B(A):
    def __init__(self):
        A.__init__(self)

But I could be mistaken.

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In Python 3.0, the super() can be called without arguments to do the same thing.

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EDIT: As pointed out by Alex, this causes infinite recursion when there is more than a single level of inheritance. Do not use this approach.

Yes, "new" style classes have a __class__ attribute available which can be used, eg.

class B(object):
    def __init__(self):
        print "B.__init__():"

class D(B):
    def __init__(self):
        print "D.__init__():"
        super(self.__class__, self).__init__()

>>> d = D()
D.__init__():
B.__init__():

>>> dir(d)
['__class__', '__delattr__', '__dict__', '__doc__', '__getattribute__', '__hash__', '__init__', '__module__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__str__', '__weakref__']
>>> d.__class__
<class '__main__.D'>

However this fails if a class were to inherit from D:

>>> class E(D):
...     pass
...
>>> E()
D.__init__():
D.__init__():
[...]
D.__init__():
D.__init__():
Traceback (most recent call last):
  File "<stdin>", line 4, in __init__
  File "<stdin>", line 4, in __init__
  [...]
  File "<stdin>", line 4, in __init__
  File "<stdin>", line 4, in __init__
RuntimeError: maximum recursion depth exceeded while calling a Python object