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How to init and malloc array to pointer on C

开发者 https://www.devze.com 2022-12-25 09:34 出处:网络
It looks like I have a memory leak when I try to initializ an array of pointers. This my code: void initLabelTable(){

It looks like I have a memory leak when I try to initializ an array of pointers. This my code:

void initLabelTable(){
    register int i;
    hashNode** hp;
    labelHashTable = (hashNode**) malloc(HASHSIZE*sizeof(hashNode*));
    hp = labelHashTable;
    for(i=0; i<HASHSIZE; i++) {
        *(hp+i) = NULL;
    }
}

Update:

I have this code:

c = fgetc(fp);

printf("%c",c);
line[MAXIMUM_LIN开发者_如何转开发E_LENGTH] = '\0';

initLabelTable();
c = fgetc(fp);

I get a segmentation fault on last row although the first getc succeeds. When I watch fp I see a different address. Any ideas?


No, this function by itself doesn't leak any memory. It allocates memory for labelHashTable, which, according to it's name, is what it's supposed to do.

Make sure that the memory pointed to by labelHashTable is freed once you're finished using it, else you will have a memory leak there. Also don't call initLabelTable() repeatedly without freeing labelHashTable before each subsequent call.

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