"foo\r\nbar".replace(/(foo).+/m, "bar")
Hello. I can not understand开发者_如何学编程 why this code does not replace foo on bar
I can not understand why this code does not replace foo on bar
Because the dot .
explicitly does not match newline characters.
This would work:
"foo\r\nbar".replace(/foo[\s\S]+/m, "bar")
because newline characters count as whitespace (\s
).
Note that the parentheses around foo
are superfluous, grouping has no benefits here.
JavaScript does not support a dot-all modifier. A common replacement is:
"foo\r\nbar".replace(/(foo)[\s\S]+/, "bar")
/m
makes ^
and $
behave correctly, but has not effect on .
.
精彩评论