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linq sort many 2 many question

开发者 https://www.devze.com 2022-12-25 06:25 出处:网络
My main entity is called [Contract]. Contract has a many 2 many relationship w/ [Service]. When I query for a list of Contracts I grab the 1st Service available like this:

My main entity is called [Contract]. Contract has a many 2 many relationship w/ [Service].

When I query for a list of Contracts I grab the 1st Service available like this:

IQueryable<Contract> q = ctx.Contracts.Skip(startRow - 1).Take(pgSize);
q.Select(c =>
         new ContractSearchResult()
         {
           ContractID = c.ContractID,
           FirstService = c.Contract2Service.FirstOrDefault().Service.Name,
           ServiceCount = c.Contract2Service.Count,
         }
        ).ToList();

(When I display this list I show the FirstService if there's only 1. If > 1 I show "My1stService (3)" to show I'm seeing the 1st of 3 services)开发者_C百科 This works fine.

My question is this:

Is there any way to sort by FirstService? Or is this impossible? I haven't found a way of expressing this in linq and allow for paging.

Any help would be appreciated.


You need to OrderBy before you page.

var result = ctx.Contracts
    .Select(c =>
        new ContractSearchResult()
        {
            ContractID = c.ContractID,
            FirstService = c.Contract2Service.FirstOrDefault().Service.Name,
            ServiceCount = c.Contract2Service.Count,
        })
 .OrderBy(x => x.FirstService)
 .Skip(startRow - 1)
 .Take(pgSize)
 .ToList();

Also note that FirstOrDefault can return null and you should check for that. If you know that it will (or should) never be null then use First instead.


q.OrderBy(c => c.Contract2Service.FirstOrDefault().Service.Name)
 .Select(c =>
        new ContractSearchResult()
        {
            ContractID = c.ContractID,
            FirstService = c.Contract2Service.FirstOrDefault().Service.Name,
            ServiceCount = c.Contract2Service.Count,
        }
    )
 .ToList();

Unless I'm missing something in your question (which is possible), it should be as simple as calling OrderBy() after your call to Select()

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