How can I sort a string "13,5,8,4,2,1,9" in ascendin开发者_Python百科g order, to get 1,2,4,5,8,9,13?

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• Split the string by commas
• Parse each substring into an integer
• Sort the resulting collection
• If you need the result to be a string (it's not clear), convert each integer back into a string and join them together with commas.

If any of those steps causes you difficulties, please be more specific.

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1. Split it into an array of items with String.split().
2. Convert to an array of numbers with Integer.valueOf().
3. Sort the array.
4. Concatenate it all back into a StringBuilder.

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As one liner, using Google Collections (updated with Kevin's suggestion)

Joiner.on(",").join(Ordering.natural().onResultOf(new Function<String, Integer>() {
    @Override
    public Integer apply(String from) {
        return Integer.valueOf(from);
    }
}).sortedCopy(Arrays.asList("4,2,7,9,1".split(","))));

• Split using String.split()
• Transform to Integer using a Function (anyone know if there's a constant for this one somewhere?)
• Sort using a TreeSet and natural ordering
• Join the parts and transform back to a String using Joiner

(old version)

Joiner.on(',').join(
    Sets.newTreeSet(
        Iterables.transform(
            Arrays.asList("13,5,8,4,2,1,9".split(",")),
            new Function<String, Integer>() {
                @Override
                public Integer apply(String from) {
                    return Integer.parseInt(from);
                }}))));

---

String s = "13,5,8,4,2,1,9";
String[] arr = s.split(",");
Arrays.sort(arr, new Comparator<String>() {
   @Override public int compare(String s1, String s2) {
      return Integer.parseInt(s1) - Integer.parseInt(s2);
   }
});
s = Arrays.toString(arr).replaceAll("[\\[ \\]]", "");

This solution uses:

• java.util.Comparator
• java.util.Arrays sort and toString
• String split and replaceAll
• regular expression

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I would tokenize the string using StringTokenizer,
parse the values (using Integer.parseInt),
then sort the results using Arrays.sort.
Lastly, re-create the string.

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String str = "13,5,8,4,2,1,9";
StringTokenizer tokens = new StringTokenizer(", ");
ArrayList<Integer> ints = new ArrayList<Integer>();
for(String token: tokens)
   ints.add(Integer.parseInt(token));

Collection.sort(ints);
String sortedStr = "";
for(int i = 0; i + 1 < ints.size(); ++i)
   sortedStr += ints.get(i) + ", ";
if (ints.size() > 0)
   sortedStr += ints.lastElement();

Might have some misspellings, but I think not. Also, add the appropriate imports yourself =)

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So you have a string containing a comma-delimited set of integers that you need to sort and then output to a string? Try split-ting the string, parse-ing the integers, sort-ing the resulting array, and then join-ing the results together

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Java 8+

If you are using Java 8 you can use streams to sort like so :

String str = "13,5,8,4,2,1,9";
String sortedString =
        Arrays.stream(str.split(","))             //split with ','
                .map(Integer::valueOf)            //convert your strings to ints
                .sorted()                         //sort 
                .map(String::valueOf)             //convert them back to string
                .collect(Collectors.joining(","));//1,2,4,5,8,9,13

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If you want an sorted array you can also use :

Integer[] sortedInts =
        Arrays.stream(str.split(","))    //split with ','
                .map(Integer::valueOf)   //convert your strings to ints
                .sorted()                //sort
                .toArray(Integer[]::new);//[1, 2, 4, 5, 8, 9, 13]

The idea is the same as Jon Skeet explanation.

---

An alternative using java.util.Scanner

public class SortString {
    public static void main( String [] args ) {
        // Read integers using Scanner...
        Scanner scanner = new Scanner( "13,5,8,4,2,1,9" ).useDelimiter(",");

        // Put them in a Integer list
        List<Integer> list = new ArrayList<Integer>();
        while( scanner.hasNextInt() ){
            list.add( scanner.nextInt() );
        }
        // And sort it
        Collections.sort( list );
        System.out.println( list );
    }
}

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ok you can try this one it work in all case.

package com.java;


import java.util.*;

public class cd
{      
  public static void main(String s[])
  {  
        Collections col;
        List l = sort(s);

        System.out.println("\nStrings sorted List ...");
        for(int i = 0; i < s.length; i++)
        {
              System.out.println((String)l.get(i));
        }

        int ints[] = {
                                719, 2, -22, 401, 6
                                };

        Integer in[] = new Integer[ints.length];            
        for(int i = 0; i < in.length; i++)
        {
              in[i] = new Integer(ints[i]);
        }

        l = sort(in);
        System.out.println("\nIntegers sorted List ...");

        for(int i = 0; i < in.length; i++)
        {
              System.out.println((Integer)l.get(i));
        }
}

public static List sort(Object o[])
{
        ArrayList al = new ArrayList();
        for(int i = 0; i < o.length; i++)
        al.add(i, o[i]);
        List list = Collections.synchronizedList(al);
        Collections.sort(list);
        return list;
}

}

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This is one way to sorting.

package com.java;


import java.util.ArrayList;

import java.util.Collections;


public class b{

public static void main(String[] args) {
//create an ArrayList object

ArrayList arrayList = new ArrayList();


//Add elements to Arraylist

arrayList.add("9");
arrayList.add("3");
arrayList.add("5");
arrayList.add("2");
arrayList.add("4");

Collections.sort(arrayList);


//display elements of ArrayList

System.out.println("ArrayList elements after sorting in ascending order : ");

for(int i=0; i<arrayList.size(); i++)

System.out.println(arrayList.get(i));



}

}

---

class SplitStr
{
  public static void main(String args[])
  {
    try
    {
      String str=args[0]+","+args[1];    //marge two string in one
      String sArr[]=str.split(",");
      int slen=sArr.length;
      int iArr[]=new int[slen];
      int temp;
      for(int i=0;i<slen;i++)
      {
       iArr[i]=Integer.parseInt(sArr[i]);   //convert String into integer array

      }
      for(int i=0;i<slen;i++)
      {
        for(int j=i+1;j<slen;j++)
        {
          if(iArr[i]>=iArr[j])
          {
            temp=iArr[i];
            iArr[i]=iArr[j];
            iArr[j]=temp;
          }
        }
      }
      for(int i=0;i<slen;i++)
      {
        System.out.println(" "+iArr[i]);
      }
    }
    catch(Exception e)
    {
      System.out.println("input error "+e);
    }
  }
}

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Bash is SO powerful :-)

numbers="1, 2, 9, 4, 7, 5" ; for number in $(echo "$numbers") ; do echo "$number" | tr -d ", "; done | sort | tr "\n" "," ; echo ""