开发者

Encode/compress sequence of repeating integers

开发者 https://www.devze.com 2022-12-25 05:22 出处:网络
I have very long integer sequences that look like this (arbitrary length!): 0000000001110002220033333

I have very long integer sequences that look like this (arbitrary length!):

0000000001110002220033333

Now I need some algorithm to convert this string into something compressed like

a9b3a3c3a2d5

Which means "a 9 times, then b 3 times, then a 3 times" and so on, where "a" stands for 0, "b" for 1, "c" for 2 and "d" for 3.

How would you do that? So far nothing suitable came to my mind, and I had no luck with google because I didn't really know what to search for. What is this kind of encoding / compression called?

PS: I am going to do the encoding with PHP, and the decoding in JavaScr开发者_开发技巧ipt.

Edit: Thank you all!

I ended up with this function for encoding:

protected function numStringToRle($s){          
        $rle    = '';
        $count = 1;
        $len    = strlen($s);
        for($i = 0; $i < $len; $i++){
            if($i != $len && isset($s[$i+1]) && $s[$i] == $s[$i+1]){
                $count++;                
            } else {
                $rle .= chr($s[$i] + 97).( $count == 1 ? '' : $count);                                
                $count = 1;
            }
        }
        return $rle;            
}

And that for decoding:

var decodeCoords = function(str) {

   str = str.replace(/(.)(\d+)/g, function(_, x, n) {
       return new Array(parseInt(n, 10) + 1).join(x);
   });

   return str.
     replace(/a/g, '0').
     replace(/b/g, '1').
     replace(/c/g, '2').
     replace(/d/g, '3');     
};


It is called Run Length Encoding

Basic encoder in PHP:

function numStringToRle($s){
    $rle = '';
    $count = 1;
    $len = strlen($s);
    for ( $i = 0; $i < $len; $i++ ){
        if ( $i != $len && $s[$i] == $s[$i+1] ){
            $count++;                
        }else{
          $rle .= chr($s[$i] + 97).$count;    
          $count = 1;
        }
    }
    return $rle;
}

Be warned it will preform badly issues with a string like

 123456789123456789

If you were going to be handling a string that may have a lot of individual single characters you would be better to add some complexity and not write the length of the run if the length of the run is 1.

//change
$rle .= chr($s[$i] + 97).$count;    

//to
$rle .= chr($s[$i] + 97).( $count == 1 ? '' : $count );   

//or
$rle .= chr($s[$i] + 97)
if ( $count != 1 ){
    $rle .= $count;
}


Here is a naive implementation of what you want.

$toEncode = '0000000001110002220033333';
$currentChar = '-1';
$length = strlen($toEncode);
$encoded = '';
$currentNbrChar = 0;
for($i = 0; $i < $length; $i++){
  if($toEncode[$i] != $currentChar){
    if($currentChar != '-1'){
      $encoded .= chr(97 + $currentChar).$currentNbrChar;
    }
    $currentNbrChar = 0;
    $currentChar = $toEncode[$i];
  }
  $currentNbrChar ++;
}
if($currentChar != '-1'){
  $encoded .= chr(97 + $currentChar).$currentNbrChar;
}
echo $encoded;


Here's a shorter version:

function smush(str) {
  return str.replace(/((.)\2*)/g, function(_, w, x) {
    return x + w.length;
  });
}

edit oh I see you want to encode with php; sorry I don't know that. Here's a decoder in a similar spirit:

function unsmush(str) {
  return str.replace(/(.)(\d+)/g, function(_, x, n) {
    return new Array(parseInt(n, 10) + 1).join(x);
  });
}


Just FYI, you could probably gzip your data and the browse will automatically unzip it. For most implementations this is going to work better than RLE. But less fun obviously.


$str="0000000001110002220033333";

//$c will count the number of occurances.

$c=1;

$lastInt=substr($str,0,1);

$str=substr($str,1);

$resultStr='';

$loopEnd=strlen($str);


for($i=1; $i<=$loopEnd+1;$i++)

{

    $nowInt=substr($str,0,1);   
    if($lastInt==$nowInt)
    {
        $c++;
        $str=substr($str,1);
    }
    else
    {
        $char=chr((int)$lastInt + 97);
        $resultStr=$resultStr.$char.$c;
        $str=substr($str,1);
        $c=1;
        $lastInt=$nowInt;
    }
}

// we use if condition since for loop will not take the last integer if it repeats.

if($c>1)
{

$char=chr((int)$lastInt + 97);

$resultStr=$resultStr.$char.$c;

}

echo $resultStr;


function compress( $str) {
$strArr = str_split($str.'0');
$count = 0;
$resStr = '';
$strCheck = $strArr[0];
foreach($strArr as $key => $value)
{
    if($strCheck == $value)
    {
       $count++;
    } 
    else
    {
        if($count == 1)
        {
            $strCheck = $value;
            $resStr .= $strArr[$key-1];
            $count=1;
        }
        elseif($count == 2)
        {
            $strCheck = $value;
            $resStr .= $strArr[$key-1].$strArr[$key-1];
            $count=1;
        }
        else
        {
            $strCheck = $value;
            $resStr .= $strArr[$key-1].$count;
            $count=1;
        }
    } 

} 
return $resStr;

}

0

精彩评论

暂无评论...
验证码 换一张
取 消

关注公众号