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sfWidgetFormChoice rendered as an unordered list

开发者 https://www.devze.com 2022-12-25 03:12 出处:网络
I\'m using symfony 1.4.3 Is there some way to render a sfWidgetFormChoice as an unordered list? In the API there is an option called \'renderer_class\' but I c开发者_高级运维an\'t find any documenta

I'm using symfony 1.4.3

Is there some way to render a sfWidgetFormChoice as an unordered list?

In the API there is an option called 'renderer_class' but I c开发者_高级运维an't find any documentation or example about it.

Thanks!


take a look at lib/vendor/symfony/lib/widget/sfWidgetFormSelect.class.php for example. Basically, what you need to do is implement a class that extends sfWidgetFormChoiceBase and write a method render() therein. A minimal example would look like this:

<?php
class sfWidgetFormChoiceUnordered extends sfWidgetFormChoiceBase
{
    public function render($name, $value = null, $attributes = array(), $errors = array())
    {
        $result = '<ul>'
        $choices = $this->getChoices();
        foreach ($choices as $choice) {
            $result .= '<li>' . $choice . '</li>';
        }
        return $result .= '</ul>';
    }
}

You can put this in /lib/widget/sfWidgetFormChoiceUnordered.class.php. Then you need to set the renderer_class option on the sfWidgetFormChoice widget like you already found out. Set it to the name of the class we just wrote: sfWidgetFormChoiceUnordered.

Example:

...
$this->addWidget('choice', new sfWidgetFormChoice(array(
    'renderer_class' => 'sfWidgetFormChoiceUnordered'
));
...

For documentation on the arguments to render(), check out the example class I posted above.

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