I have a vector of vectors:
开发者_如何学Govector< vector<int> > BigVec;
It contains an arbitrary number of vectors, each of an arbitrary size. I want to delete not duplicate elements of each vector, but any vectors that are the exact same as another. I don't need to preserve the order of the vectors so I can sort etc..
It should be a really simple problem to solve but I'm new to this, my (not-working) best effort:
for (int i = 0; i < BigVec.size(); i++)
{
for (int j = 1; j < BigVec.size() ; j++ )
{
if (BigVec[i][0] == BigVec [j][i]);
{
BigVec.erase(BigVec.begin() + j);
i = 0; // because i get the impression deleting a
j = 1; // vector messes up a simple iteration through
}
}
}
I think there might be a solution using Unique(), but I can't get that to work either.
Why not use unique? I think if you're having problems getting it to work it's because using std::unique
requires that the range be sorted. So, something like
std::vector<std::vector<int>> myVec;
std::sort(myVec.begin(), myVec.end());
myVec.erase(std::unique(myVec.begin(), myVec.end()), myVec.end());
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