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Encoding gives "'ascii' codec can't encode character … ordinal not in range(128)"

开发者 https://www.devze.com 2022-12-24 19:16 出处:网络
I am working through the Django RSS reader project here. The RSS feed will read something like \"OKLAHOMA CITY (AP) — James Harden let\".The RSS feed\'s encoding reads encoding=\"UTF-8\" so I believ

I am working through the Django RSS reader project here.

The RSS feed will read something like "OKLAHOMA CITY (AP) — James Harden let". The RSS feed's encoding reads encoding="UTF-8" so I believe I am passing utf-8 to markdown in the code snippet below. The em 开发者_开发问答dash is where it chokes.

I get the Django error of "'ascii' codec can't encode character u'\u2014' in position 109: ordinal not in range(128)" which is an UnicodeEncodeError. In the variables being passed I see "OKLAHOMA CITY (AP) \u2014 James Harden". The code line that is not working is:

content = content.encode(parsed_feed.encoding, "xmlcharrefreplace")

I am using markdown 2.0, django 1.1, and python 2.4.

What is the magic sequence of encoding and decoding that I need to do to make this work?


(In response to Prometheus' request. I agree the formatting helps)

So in views I add a smart_unicode line above the parsed_feed encoding line...

content = smart_unicode(content, encoding='utf-8', strings_only=False, errors='strict')
content = content = content.encode(parsed_feed.encoding, "xmlcharrefreplace") 

This pushes the problem to my models.py for me where I have

def save(self, force_insert=False, force_update=False): 
     if self.excerpt: 
         self.excerpt_html = markdown(self.excerpt) 
         # super save after this 

If I change the save method to have...

def save(self, force_insert=False, force_update=False): 
     if self.excerpt: 
         encoded_excerpt_html = (self.excerpt).encode('utf-8') 
         self.excerpt_html = markdown(encoded_excerpt_html)

I get the error "'ascii' codec can't decode byte 0xe2 in position 141: ordinal not in range(128)" because now it reads "\xe2\x80\x94" where the em dash was


If the data that you are receiving is, in fact, encoded in UTF-8, then it should be a sequence of bytes -- a Python 'str' object, in Python 2.X

You can verify this with an assertion:

assert isinstance(content, str)

Once you know that that's true, you can move to the actual encoding. Python doesn't do transcoding -- directly from UTF-8 to ASCII, for instance. You need to first turn your sequence of bytes into a Unicode string, by decoding it:

unicode_content = content.decode('utf-8')

(If you can trust parsed_feed.encoding, then use that instead of the literal 'utf-8'. Either way, be prepared for errors.)

You can then take that string, and encode it in ASCII, substituting high characters with their XML entity equivalents:

xml_content = unicode_content.encode('ascii', 'xmlcharrefreplace')

The full method, then, would look somthing like this:

try:
    content = content.decode(parsed_feed.encoding).encode('ascii', 'xmlcharrefreplace')
except UnicodeDecodeError:
    # Couldn't decode the incoming string -- possibly not encoded in utf-8
    # Do something here to report the error


Django provides a couple of useful functions for converting back and forth between Unicode and bytestrings:

from django.utils.encoding import smart_unicode, smart_str


I encountered this error during a write of a file name with zip file. The following failed

ZipFile.write(root+'/%s'%file, newRoot + '/%s'%file)

and the following worked

ZipFile.write(str(root+'/%s'%file), str(newRoot + '/%s'%file))
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