In following program . I have one doubt. I have declared one global variable . I am
printing the address of the global variable in the function . It is giving me same address when I am not changing the value of global . If I did any changes in the global variables It is giving me different address why...........? Like that it is happening for static also.#include<stdio.h>
int global=1开发者_JS百科0 ; // Global variables
void function();
main()
{
global=20;
printf ( " %p \n" , global ) ;
printf ( " Val: %d\n", global ) ;
function();
new();
}
void function()
{
global=30;
printf ( " %p \n" , global ) ;
printf ( " Val: %d\n", global ) ;
}
Thanks.
You are not printing the address of the global, you are printing its value. To print the address:
printf ( " %p \n" , & global ) ;
Note the ampersand, which is the "address-of" operator. The "%p" formatter only controls output format, it doesn't make printf() magically take the address for you.
You are not printing the address of the variable.
To print the address:
printf("%p\n", &global);
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