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How to pass the equivalent of nil for an (NSError **)

开发者 https://www.devze.com 2022-12-24 15:15 出处:网络
I have a method that takes an (NSError **) but I don\'t want to pass it one. When I pass it \"nil\" or \"NULL\" I end up with \"EXC_BAD_开发者_运维问答ACCESS\".

I have a method that takes an (NSError **) but I don't want to pass it one. When I pass it "nil" or "NULL" I end up with "EXC_BAD_开发者_运维问答ACCESS".

The offending line is "*error = nil;"

How do I pass it the equivalent of "nil" without crashing?


The offending line should be:

if (error != nil) { *error = nil; }

You're trying to dereference a null pointer, which is a surefire way to crash.

The alternative would be to pass it an NSError**, but then just ignore it afterwards.


When you are implementing such method, you can use the following trick so that you won’t have to check for nil all the time:

- (void) doSomethingMaybeCausing: (NSError**) error
{
    NSError *dummyError = nil;
    if (error == NULL)
        error = &dummyError;
    // ...later:
    *error = [NSError …];
}

Now the caller can pass NULL if he’s not interested in the errors.


You have to pass it a valid pointer to something which it can modify. The standard way to do this would be:

NSError *error = nil;
[object callMethod:whatever error:&error];
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