How do I have开发者_开发问答 my UISlider
go from 1-100
in increments of 5
?
Add a target like this:
slider.continuous = YES;
[slider addTarget:self
action:@selector(valueChanged:)
forControlEvents:UIControlEventValueChanged];
And in the valueChanged function set the value to the closest value that is divisible by 5.
[slider setValue:((int)((slider.value + 2.5) / 5) * 5) animated:NO];
So if you need any interval other than 5 simply set it like so:
float interval = 5.0f;//set this
[slider setValue:interval*floorf((slider.value/interval)+0.5f) animated:NO];
A slightly more elegant solution in Swift could be something like this
let step: Float = 5
@IBAction func sliderValueChanged(sender: UISlider) {
let roundedValue = round(sender.value / step) * step
sender.value = roundedValue
// Do something else with the value
}
This way you get steps of 5. You can read more about the setup in my post.
There is another way to active the stepper functionality. works in a general case
Example:
range of data is 0 - 2800 and I want the increments to be in 25 unit values. I would do the following
- set up the range of the slider to be 0 - (maxRange/unitsteps).
- when the value changed method runs use (int)slider.value * unitsteps .
in the example above my slider would be set in IB to range 0 - 112. and my code would be (int)slider.value * 25.
if you then have a text field that can be modified for direct input you would just do the opposite set the slider value to the [textfield.text intValue]/ unitsteps.
For anyone looking for the Swift syntax...
override func viewDidLoad() {
super.viewDidLoad()
mySlider.addTarget(self, action: "sliderValueDidChange:", forControlEvents: .ValueChanged)
}
func sliderValueDidChange(sender:UISlider!)
{
//Set value to the nearest 5...
print((Float)((Int)((sender.value + 2.5) / 5) * 5))
sender.setValue((Float)((Int)((sender.value + 2.5) / 5) * 5), animated: false)
}
Alternatively, just create an Action function with the Assistant Editor (what I did ultimately)...
@IBAction func mySliderValueChanged(sender: UISlider) {
//Set value to the nearest int
sender.setValue(Float(roundf(sender.value)), animated: false)
}
In swift 3, slider with increments +/- 7:
@IBOutlet weak var sldComponent: UISlider!
...
sldComponent.addTarget(self, action: #selector(_sldComponentChangedValue),for: .valueChanged)
...
func _sldComponentChangedValue(sender: UISlider!) {
self.sldComponent.setValue((round(sender.value / 7) * 7), animated: false)
print("\(sender.value)")
}
Why not just:
@IBAction func onSlider(_ sender: UISlider) {
let value = Int(sender.value)
if value % 5 == 0 {
// handle(value) ...
}
}
1. In storyboard mode, drag and drop a stepper and label. the label will show the stepper values.
- left click and drag both label and stepper to your view controller as outlets.
name label as "stepperValue"
- drag and drop stepper again making it a func- I called mine "func"
@IBAction func inc(sender: AnyObject) {
stepperValue.text = "(Int(stepper.value) * 5 )"
click the stepper and it will increment by 5
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