//Inherits="System.Web.Mvc.ViewPage<FilmFestWeb.Models.ListVideosViewModel>"
<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server开发者_如何学编程">
<h2>ListVideos</h2>
<% foreach(BusinessObjects.Video vid in Model.VideoList){%>
<div class="videoBox">
<%= Html.Encode(vid.Name) %>
<img src="<%= vid.ThumbnailImage %>" />
</div>
<%} %>
</asp:Content>
//ListVideosViewModel
public class ListVideosViewModel
{
public IList<Video> VideoList { get; set; }
}
//Video
public class Video
{
public long VideoId { get; set; }
public long TeamId { get; set; }
public string Name { get; set; }
public string Tags { get; set; }
public string TeamMembers { get; set; }
public string TranscriptFileName { get; set; }
public string VideoFileName { get; set; }
public int TotalNumRatings { get; set; }
public int CumulativeTotalScore { get; set; }
public string VideoUri { get; set; }
public Image ThumbnailImage { get; set; }
}
I am getting the "red x" that I usually associate with image file not found. I have verified that my database table shows after the stored proc that uploads the image executes. Any insight or advice would be greatly appreciated.
As i see you are using mvc use this look at the example imagedata is byte[] array and imagemimetype is a string this is an example of an action in your controller
public FileContentResult GetImage(int ProductID)
{
Product product = (from p in productsRepository.Products
where p.ProductID == ProductID
select p).First();
return File(product.ImageData, product.ImageMimeType);
}
use this to show the image in the view
<img src="<%= Url.Action("GetImage", "Products",
new { Model.ProductID }) %>" />
You will not be returning an Image from you database. You will be getting a byte[]. My recommendation would be to create a ASP.NET Handler that returns images from the DB. Then you can link to the handler.
Look at this SO post for how to do that: Dynamically Rendering asp:Image from BLOB entry in ASP.NET
Thank you for the help. This is how I solved the issue (uses entlib 4.1)
public ThumbnailImage GetThumbnailImageByVideoId( long videoId )
{
Database db = DatabaseFactory.CreateDatabase("Connection String");
DataSet ds = new DataSet();
ThumbnailImage img = null;
try
{
using (DbCommand cmd = db.GetStoredProcCommand("usp_GetThumbnailImageByVideoId"))
{
db.AddInParameter(cmd, "VideoId", DbType.Int64, videoId);
db.LoadDataSet(cmd, ds, "Video");
}
foreach (DataRow dr in ds.Tables["Video"].Rows)
{
if (! string.IsNullOrEmpty(dr["ThumbnailImage"].ToString()))
{
byte[] b = dr["ThumbnailImage"] as byte[];
MemoryStream ms = new MemoryStream(b);
img = new ThumbnailImage();
img.Image = Image.FromStream(ms);
img.ContentType = dr["ImageContentType"].ToString();
}
break;
}
}
catch (Exception ex)
{
throw ex;
}
return img;
}
精彩评论