can we convert integer into character

we can convert character to an integer equivalent to the ASCII value of the same but can we do the reverse thing ie convert a given ASCII value to its cha开发者_如何转开发racter equivalent?

public String alphabets(int[] num)
{
char[] s = new char[num.length];
String str = new String();
for(int i=0; i< num.length; i++)
{   
    s[i] = 'A' + (char)(num[i]- 1);
    str += Character.toString(s[i]);
}
return str;         
}

shows possible lost of precision error ...

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To convert to/from:

int i = 65;
char c = (char)i;

char c = 'A';
int i = (int)c;

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The error is more complex than you would initially think, because it is actually the '+' operator that causes the "possible loss of precision error". The error can be resolved if the cast is moved:

s[i] = (char)('A' + (num[i]- 1));

Explanation
In the first bullet list of §5.6.2 Binary Numeric Promotion in the Java Language Specification it is stated that:

When an operator applies binary numeric promotion to a pair of operands [...] the following rules apply, in order, using widening conversion (§5.1.2) to convert operands as necessary:

• If any of the operands is of a reference type, unboxing conversion (§5.1.8) is performed. Then:
• If either operand is of type double, the other is converted to double.
• Otherwise, if either operand is of type float, the other is converted to float.
• Otherwise, if either operand is of type long, the other is converted to long.
• Otherwise, both operands are converted to type int.

In the next bullet list it is stated that:

Binary numeric promotion is performed on the operands of certain operators:

• The multiplicative operators *, / and % (§15.17)
• The addition and subtraction operators for numeric types + and - (§15.18.2)
• The numerical comparison operators , and >= (§15.20.1)
• The numerical equality operators == and != (§15.21.1)
• The integer bitwise operators &, ^, and | (§15.22.1)
• In certain cases, the conditional operator ? : (§15.25)

In your case, that translates to:

s[i] = (int)'A' + (int)((char)(num[i] - (int)1));

hence the error.

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You actually don't even need a cast:

char c = 126;

And this actually appears to work for unicode characters as well. For example try:

 System.out.println((int) 'โ'); // outputs 3650, a thai symbol
 char p = 3650;
 System.out.println(p); // outputs the above symbol

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Character.toChars:

public static char[] toChars(int codePoint)

Converts the specified character (Unicode code point) to its UTF-16 representation stored in a char array.

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Doesn't casting to char work?

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There are several ways. Look at the Character wrapper class. Character.digit() may do the trick. Actually this does the trick!!

Integer.valueOf('a')