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Segmentation fault before return

开发者 https://www.devze.com 2022-12-24 00:45 出处:网络
Why does the following code seg fault before returning: int main() { char iD[20]; memset (iD, 0, 20); char* prefix;

Why does the following code seg fault before returning:

int main()
{
char iD[20];
memset (iD, 0, 20);

char* prefix;
srand (time(NULL) );
int iPrefix = rand()%1000000;

sprintf(prefix, "%i", iPrefix);
int len = strlen(prefix);

char* staticChar = "123456789";

//set prefix into ID
memcpy(iD, prefix, len);
// append static value
memcpy(iD+len, staticChar, 20-len);

cout << "END " << endl;

re开发者_如何学运维turn 0;
}

At the minute, the cout will display, but I get a segmentation fault.


You need to allocate memory for prefix before calling this:

sprintf(prefix, "%i", iPrefix);

or you could refactor the code e.g.,

snprintf(iD, sizeof(iD), "%i%s", iPrefix, staticChar);


char* prefix;
//some code

sprintf(prefix, "%i", iPrefix);

You forgot to assign some memory to prefix.


no memory has been allocated to prefix. so it can access any memory location which which generates segmentation fault , in simple words.

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