How do I get the day (1-7) from a Unix timestamp in PHP? I also need the day d开发者_如何学JAVAate (1-31) and month (1-12).
You can use date() function
$weekday = date('N', $timestamp); // 1-7
$month = date('m', $timestamp); // 1-12
$day = date('d', $timestamp); // 1-31
see http://docs.php.net/getdate
e.g.
$ts = time(); // could be any timestamp
$d=getdate($ts);
echo 'day of the week: ', $d['wday'], "\n";
echo 'day of the month: ', $d['mday'], "\n";
echo 'month: ', $d['mon'], "\n";
It's the date() function you're after.
You can get more details from the PHP manual but in a nutshell here are the functions you need.
date('N', $timestamp);
//numeric representation of the day of the week
date('j', $timestamp);
//Day of the month without leading zeros
date('n', $timestamp);
//Numeric representation of a month, without leading zeros
Use the date function as stated before, with your $timestamp
as the second argument:
$weekday = date('N', $timestamp); // 1 = Monday to 7 = Sunday
$month = date('m', $timestamp); // 1-12 = Jan-Dec
$day = date('d', $timestamp); // 1-31, day of the month
Not all PHP versions play nice with negative timestamps. My experience is that timestamps dating back to before the UNIX epoch fare better with the new DateTime object.
print "Week".date('N')."\n";
print "day of month " .date('d')."\n";
print "month ".date('m')."\n";
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