A preprocessor definition that includes defined(X)
will never evaluate to true, but (defined X)
will. This occurs in MSVC9; I have not tested other preprocessors. A simple example:
#define FEATURE0 1
#define FEATURE1 0
#define FEATURE2 1
#define FEATURE3 (FEATURE0 && !FEATURE1 && (defined(FEATURE2)))
#define FEATURE4 (FEATURE0 && !FEATURE1 && (defined FEATURE2))
#define FEATURE5 (FEATURE0 && !FEATURE1 && (defined (FEATURE2)))
#if FEATURE3
#pragma message("FEATURE3 Enabled")
#elif (FEATURE0 && !FEATURE1 && (defined(FEATURE2)))
#pragma message("FEA开发者_StackOverflowTURE3 Enabled (Fallback)")
#endif
#if FEATURE4
#pragma message("FEATURE4 Enabled")
#elif (FEATURE0 && !FEATURE1 && (defined FEATURE2))
#pragma message("FEATURE4 Enabled (Fallback)")
#endif
#if FEATURE5
#pragma message("FEATURE5 Enabled")
#elif (FEATURE0 && !FEATURE1 && (defined (FEATURE2)))
#pragma message("FEATURE5 Enabled (Fallback)")
#endif
The output from the compiler is:
1>FEATURE3 Enabled (Fallback)
1>FEATURE4 Enabled 1>FEATURE5 EnabledWorking cases: defined (X)
, defined( X )
, and defined X
.
defined(X)
Why is defined
evaluated differently when part of a definition, as in the #if
cases in the example, compared to direct evaluation, as in the #elif
cases in the example?
defined
is specific to #if
and #elif
. When using it through macro expansion the behavior is undefined.
Remember that defined(X)
isn't interpreted like a function call (a la sizeof(X)
), it's parsed by a special language parser. This parser recognizes defined
as a modifier to an if
statement, not as an independent entity. When you are using defined(FEATURE2)
, it is not treating defined
as a keyword but instead as a regular object or #define
d entity (which doesn't exist in this case, causing your error). Later, when you use it inside the elif
statement, the parser treats it as a proper keyword.
To be honest, I wasn't aware that defined(SOMETHING)
would work in any case.
According to 6.10.1.3 in the C99 spec, the keyword defined is only recognized if it appears directly in the expression of the #if before any macro expansion in that expression. If macro expansion results in the keyword defined, the results are undefined.
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