I have$('.class:first'), I want $(.class:fourth') using jquery

I can select the first item in the div using

$('.class:first')

Now since I w开发者_StackOverflow社区ill have random id values, and the class remains the same, I want to access the id of the fourth element, will it be something like this

$('.class:fourth')

using jQuery.

Thanks Jean

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There are several ways of doing this. Firstly you can use the :eq(n) pseudo-element:

$(".class:eq(3)")...

:eq(n) is zero-based so :eq(3) is the fourth instance. You can also use eq():

$(".class").eq(3)...

The correct answer is not:

$(".class:nth-child(4)")...

What's the difference? The last one finds all elements that have a class of "class" that are the fourth child of something. That could be zero or many elements.

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$('.class:nth(4)')

UPDATE:

Actually it's $('.class:nth-child(4)')

UPDATE2:

The correct answer is given by @cletus with a great explanation of the differences between nth-child and eq selector:

$('.class:eq(3)')

Please mark his answer as correct.

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Or you can do $("expr").eq(2) - detail here