Let's say I have a grammar defined to something like:
some_rule := a b [c [d]]
where c
, and d
are optional and default to a certain value (let's say 14) if not given. Can I get it to default to the 14 if the value isn't given? I want the produced std::vector
to always be of size 4.
The closest I've come is like the following:
qi::rule<Iterator, std::vector<int>(), ascii::space_type> some_rule;
some_rule %= int_ >> int_ >> -int_ >> -int_;
// ...
some_other_rule = some_rule[&some_callback_for_int_vectors];
which will then get 0 for the optional values that didn't show up (I believe). I then change consecutive 0s at the end into 14. Not only is this horribly wrong, but it's also just not elegant. Is there a bet开发者_C百科ter way to do this?
It looks like you can do this with the boost::qi::attr
auxiliary parser.
int default_value = 14;
qi::rule<Iterator, int(), ascii::space_type> some_optional_rule;
qi::rule<Iterator, std::vector<int>(), ascii::space_type> some_rule;
some_optional_rule %= int_ | attr(default_value);
some_rule %= repeat(2)[int_] >> repeat(2)[some_optional_rule];
I'm still not sure if this is the best way to do this though.
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