#include<conio.h>
#include<stdio.h>
#define abc 7
int main()
{
int abc=1;
printf("%d",abc);
getch();
return 0;
}
why this program is giving com开发者_运维百科pile time error
You're assigning 7=1
which is invalid. Since you've defined abc
to be 7, the preprocessor translates the line:
int abc=1;
to:
int 7=1;
Which is a syntax error in C (my gcc
says syntax error before numeric constant).
You define abc
as 7
.
Then int abc=1
is transformed into int 7=1
which is absurd.
Why are you doing this?
You declare "abc" macro value as 7 . So if again include the macro name as variable, it will give error.
consider the following
abc value is 7. So it will treated as 7=1. So that it will give error.
The C preprocessor does a blind replacement of abc
with 7
resulting in:
int 7=1;
which clearly is an error.
When the preprocessor replaces abc
with 7
, the following line becomes invalid:
int 7=1;
An identifier in C, can't be just a number.
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