Formatting numbers by tokens with php

I'm looking for a way to format numbers using "tokens". This needs to be conditional (for the first few leading characters).

Example:

<?php
 $styles=array('04## ### ###',开发者_运维知识库'0# #### ####','13# ###','1800 ### ###');
 format_number(0412345678); /*should return '0412 345 678'*/
 format_number(0812345678); /*should return '08 1234 5678'*/
 format_number(133622); /*should return '133 622'*/
 format_number(1800123456); /*should return '1800 123 456'*/
?>

Incase you haven't guessed, my use of this is to format Australian phone numbers, dependent on their 'type'.

I have a PHP function that does this, but it is ~114 lines and contains a lot of repeated code.

Can anyone help?

---

foreach ($styles as $style) {
    $pattern = sprintf(
        "/^%s$/D",
        str_replace(array(' ', '#'), array('', '\d'), $style)
    );

    if (preg_match($pattern, $phoneNumber)) {
        return vsprintf(
            preg_replace('/\S/', '%s', $style),
            str_split($phoneNumber)
        );
    }
}
return $phoneNumber;

$styles should be ordered by precedence. Maybe the length of the initial mask of numbers should dictate precedence, in which case you could use

usort($styles, function($a, $b) {
    return strspn($b, '0123456789') - strspn($a, '0123456789');
});

---

just a toy example

$number="0412345678";
$styles=array('04## ### ###','0# #### ####','13# ###','1800 ### ###');
$whatiwant = preg_grep("/04/i",$styles);  #04 is hardcoded. 
$s = explode(" ",$whatiwant[0]);
$count= array_map(strlen,$s);
$i=0;
foreach($count as $k){
  print substr($number,$i,$k)." ";
  $i=$k;
}

output

$ php test.php
0412 345 234