I have a year value and a day of ye开发者_开发百科ar and would like to convert to a date (day/month/year).
datetime.datetime(year, 1, 1) + datetime.timedelta(days - 1)
>>> import datetime
>>> datetime.datetime.strptime('2010 120', '%Y %j')
datetime.datetime(2010, 4, 30, 0, 0)
>>> _.strftime('%d/%m/%Y')
'30/04/2010'
The toordinal()
and fromordinal()
functions of the date
class could be used:
from datetime import date
date.fromordinal(date(year, 1, 1).toordinal() + days - 1)
since it is pretty common these days, a pandas
option, using pd.to_datetime
with specified unit and origin:
import pandas as pd
day, year = 21, 2021
print(pd.to_datetime(day-1, unit='D', origin=str(year)))
# 2021-01-21 00:00:00
>>>import datetime
>>>year = int(input())
>>>month = int(input())
>>>day = int(input())
data = datetime.datetime(year,month,day)
daynew = data.toordinal()
yearstart = datetime.datetime(year,1,1)
day_yearstart = yearstart.toordinal()
print ((daynew-day_yearstart)+1)
Using the mx.DateTime module to get the date is similar to what has been proposed above using datetime
and timedelta
. Namely:
import mx.DateTime as dt
date = dt.DateTime(yyyy,mm,dd) + dt.DateTimeDeltaFromDays(doy-1)
So, given that you know the year (say, 2020) and the doy (day of the year, say 234), then:
date = dt.DateTime(2020,1,1) + dt.DateTimeFromDays(233)
which returns
2020-08-21 00:00:00.00
The advantage of the mx.DateTime library is that has many useful features. As per description in its homepage:
- Parses date/time string values in an almost seamless way.
- Provides conversion routines to and from many different alternative date/time storage formats.
- Includes an easy-to-use C API which makes integration a breeze.
- Fast, memory efficient, accurate.
- Georgian and Julian calendar support.
- Vast range of valid dates (including B.C. dates).
- Stable, robust and portable (mxDateTime has been around for almost 15 years now).
- Fully interoperates with Python's time and datetime modules.
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