I asked some time ago on an account I can'开发者_如何学Got remember how to manipulate basic pointers and someone gave me a really good demo
for example
char *ptr = "hello" (hello = a char array)
so now *ptr
is pointing at 'h'
ptr++
means moving the ptr
to point at the next element, to get its value I do *ptr
and that gives me e
ok so far everything works as I hope :D, but now I need to manipulate a char **ptr
and was wondering how I do this in a way that mimics the effects of a 2d array?
Some basic tips would be much appreciated as I need to do an assignment that has a **ptr
to imitate a 2d array and without knowing how it does this first means I can't even solve it on paper (for example, how do you dereference a **ptr
, how do you get [x][y]
values etc)
thanks
You can subscript a pointer the same way you can subscript an array, provided all the addresses have been set up correctly.
Assuming the following declaration:
char **ptr;
here are the types of the various expressions:
Expression Type Equivalent expressions (yield same value) ---------- ---- ----------------------------------------- ptr char ** &ptr[0] *ptr char * ptr[0] *(ptr+i) char * ptr[i]; &ptr[i][0] **ptr char ptr[0][0] *(*(ptr+i)) char ptr[i][0]; *ptr[i] *(*(ptr+i)+j) char ptr[i][j]
thus:
ptr
can be treated as though it was an array of strings (2-d array of char)ptr[i]
points to the beginning of the i'th string in the listptr[i][j]
is the value of the j'th character of the i'th string in the list- The expressions
ptr++
and++ptr
will advanceptr
to point to the next string - The expressions
(*ptr)++
and++(*ptr)
will advance*ptr
to point to the next character
As for setting up your pointers, this arrangement assumes everything has already been allocated as static arrays or dynamically through malloc
. You cannot just write
char **ptr = {"foo", "bar", "bletch"}; // using aggregate initializer on
// non-aggregate type; bad juju,
// a.k.a undefined behavior
or
char **ptr; // ptr has not been initialized to point anywhere
ptr[0] = "foo"; // dereferencing ptr via subscript invokes undefined
ptr[1] = "bar"; // behavior
ptr[2] = "bletch";
Generally, when you're using a pointer as though it was an array, you'll use malloc
or something similar to allocate your buffers:
char **ptr = malloc(sizeof *ptr * N);
if (ptr)
{
ptr[0] = "foo"; // ptr[i] gets address of
ptr[1] = "bar"; // string literal
ptr[2] = "bletch";
...
}
or
char **ptr = malloc(sizeof *ptr * N);
if (ptr)
{
size_t i;
for (i = 0; i < N; i++)
{
ptr[i] = malloc(sizeof *ptr[i] * M); // strictly speaking, the sizeof
if (ptr[i]) // is not necessary here
{
//initialize ptr[i]
}
}
}
A pointer to a pointer is just that. For example:
// Declare our double-indirection pointer.
char** ptr;
// And initialize it:
char s1[] = "hello";
char s2[] = "world";
ptr = malloc(sizeof(char*) * 2);
ptr[0] = s1;
ptr[1] = s2;
// ptr now points to a pointer that points to 'h'.
char* ptr2 = *ptr;
// ptr2 points to 'h'.
char* ptr3 = *(ptr + 1);
// ptr3 points to "w".
char c = **ptr; // could be written as *(*ptr)
// c = 'h'.
char c2 = *(*(ptr + 1));
// c2 = 'w'.
char c3 = *(*(ptr) + 1);
// c3 = 'e'.
You may use them as you would a normal two-dimensional array. (Since effectively, that's what they are)
char** ptr = {"lorem", "ipsum", "dolor"};
char* s1 = ptr[0]; //Points to the beginning of "lorem"
char* s2 = ptr[1]; //Points to the beginning of "ipsum"
char c = ptr[2][4]; //Contains 'r'
This is due to the fact that:
int *a;
//...
int i = a[6];
int j = *(a + 6); //Same as previous line!
Cheers,
Amit Ron--
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