referring to yesterday's post,
this woke me up this morning. Why does this actually work? As long as the function test
is concerned, this function has no body so how can it perform anything? I want to know why and how this works? I'm REALLY interested to see your answers.
template<typename T>
class IsClassT {
private:
typedef char One;
typedef struc开发者_Python百科t { char a[2]; } Two;
template<typename C> static One test(int C::*); //NO BODY HERE
template<typename C> static Two test(…); //NOR HERE
public:
enum { Yes = sizeof(IsClassT<T>::template test<T>(0)) == sizeof(One) };
enum { No = !Yes };
};
Thanks in advance with help to understand this very interesting phenomenon.
You can not get compiler error because
test
-function declaration exists.You can not get linker error because you do not call
test
-function.
C++ Standart ISO/IEC 14882:2003(E)
5.3.3 Sizeof
The sizeof operator yields the number of bytes in the object representation of its operand. The operand is either an expression, which is not evaluated, or a parenthesized type-id. The sizeof operator shall not ...
...
I assume you are refering to the Yes enum? IsClassT<T>::test<T>(0)
? sizeof does not actually evaluate its arguments. That's why code like the following is legal, even though you might expect it to bail out on you:
int* p = 0;
int sizeof_int = sizeof(*p); //oops, p is 0 :(
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