yield in ERB without rails

H开发者_如何学Cow can I use yield for template inheritance in erb? I want to use erb in a plain ruby CGI script and want to use a base template and subtemplate like it Rails with the application template does.

---

def a
  ERB.new('<%= yield %>').result(binding)
end
a{123}
#=> "123"

It's important that the call to Kernel#binding be inside a method, that way the context includes the block (ERB#result won't take a block).

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Check out Tilt (http://github.com/rtomayko/tilt/). It's the gem that handles templating in Sinatra and it provides ERB yields along with many other nice features.

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You can use Tilt but if you don't want to add an extra dependency, here's a better example on how you can yield in erb:

require "erb"

class Controller
  TEMPLATE = ERB.new("Hello <%= @someone %>\n\n<%= yield %>")

  def initialize(someone)
    @someone = someone
  end

  def render
    TEMPLATE.result(self.get_binding { yield })
  end

  def get_binding
    binding
  end
end

puts Controller.new("World").render { "I'm Jack" }
# =>
Hello World

I'm Jack

I found the answer here.

---

I don't think you can - Rails provides that infrastructure as part of actionpack.

What you may be able to do is take actionpack and add it into your script.

Alternatively you could roll a lightweight templating system yourself.

Alternatively alternatively use Rails or Merb or Sinatra.

---

app.rb

require 'erb'

class Template
    def render(template_name="base")
        ERB.new(File.read("#{template_name}.erb")).result(binding)
    end
end

result = Template.new.render do
    ERB.new(File.read("index.erb")).result
end

puts result

base.erb

<main>
    <%= render "footer" %>
    <%=yield %>
</main>

index.erb

<h1>Index Page</h1>

footer.erb

<h1>Footer here</h1>

output image: