Not sure how to take my current expression and get the week ending date of the week.
My current expression returns the date, one week from today.
开发者_如何学CDateAdd(DateInterval.WeekOfYear, 1, today())
What I want to do instead is return the end date (Saturday) of that week instead.
What do I need to add to this expression to get the desired result?
Thanks!
Okay, looks like I've got it but it's ugly. Can anyone help me streamline this?
Here's what I have, based on turning Raj's example into an expression:
="One Week Projected Backlog w/e "& DateAdd(DateInterval.Day, -1 * DatePart(DateInterval.WeekDay, (DateAdd(DateInterval.WeekOfYear, 1, today()))) + 7, (DateAdd(DateInterval.WeekOfYear, 1, today())))
Try this
Declare @DateValue DateTime = '3/1/2010'
select DATEADD (D, -1 * DatePart (DW, @DateValue) + 7, @DateValue)
I basically calculated what day of the week then incoming date was, and then soft-computed the beginning of the week with the -1 multiplier, and traversed forward to the Saturday by adding 7 to it.
Of course, this will only work if you SQL Server is set to the week starting on Sunday
For SQL Server reporting services, I think this should work for Sat of current week
DATEADD (DateInterval.Day, -1 * DatePart (DateInterval.DayOfWeek, Today()) + 7, Today())
For Sat of next week
DATEADD (DateInterval.Day, -1 * DatePart (DateInterval.DayOfWeek, Today()) + 14, Today())
How about?
select dateadd(ww,-2,'1-27-2014')+4
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