I have a requirement for the generation of a given number N of vectors of given size each consistent of a uniform distribution of 0s and 1s.
This is what I am doing at the moment, but开发者_开发百科 I noticed that the distribution is strongly peaked at half 1s and half 0s, which is no good for what I am doing:
a = randint(1, sizeOfVector, [0 1]);
The unifrnd
function looks promising for what I need, but I can't manage to understand how to output a binary vector of that size.
Is it the case that I can use the unifrnd
function (and if so how would be appreciated!) or can is there any other more convenient way to obtain such a set of vectors?
Any help appreciated!
Note 1: just to be sure - here's what the requirement actually says:
randomly choose N vectors of given size that are uniformly distributed over [0;1]
Note 2: I am generating initial configurations for Cellular Automata, that's why I can have only binary values [0;1].
To generate 1 random vector with elements from {0, 1}:
unidrnd(2,sizeOfVector,1)-1
The other variants are similar.
If you want to get uniformly distributed 0's and 1's, you want to use randi. However, from the requirement, I'd think that the vectors can have real values, for which you'd use rand
%# create a such that each row contains a vector
a = randi(1,N,sizeOfVector); %# for uniformly distributed 0's and 1's
%# if you want, say, 60% 1's and 40% 0's, use rand and threshold
a = rand(N,sizeOfVector) > 0.4; %# maybe you need to call double(a) if you don't want logical output
%# if you want a random number of 1's and 0's, use
a = rand(N,sizeOfVector) > rand(1);
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