I want to know the disadvant开发者_如何学Cages of scanf()
.
In many sites, I have read that using scanf
might cause buffer overflows. What is the reason for this? Are there any other drawbacks with scanf
?
Most of the answers so far seem to focus on the string buffer overflow issue. In reality, the format specifiers that can be used with scanf
functions support explicit field width setting, which limit the maximum size of the input and prevent buffer overflow. This renders the popular accusations of string-buffer overflow dangers present in scanf
virtually baseless. Claiming that scanf
is somehow analogous to gets
in the respect is completely incorrect. There's a major qualitative difference between scanf
and gets
: scanf
does provide the user with string-buffer-overflow-preventing features, while gets
doesn't.
One can argue that these scanf
features are difficult to use, since the field width has to be embedded into format string (there's no way to pass it through a variadic argument, as it can be done in printf
). That is actually true. scanf
is indeed rather poorly designed in that regard. But nevertheless any claims that scanf
is somehow hopelessly broken with regard to string-buffer-overflow safety are completely bogus and usually made by lazy programmers.
The real problem with scanf
has a completely different nature, even though it is also about overflow. When scanf
function is used for converting decimal representations of numbers into values of arithmetic types, it provides no protection from arithmetic overflow. If overflow happens, scanf
produces undefined behavior. For this reason, the only proper way to perform the conversion in C standard library is functions from strto...
family.
So, to summarize the above, the problem with scanf
is that it is difficult (albeit possible) to use properly and safely with string buffers. And it is impossible to use safely for arithmetic input. The latter is the real problem. The former is just an inconvenience.
P.S. The above in intended to be about the entire family of scanf
functions (including also fscanf
and sscanf
). With scanf
specifically, the obvious issue is that the very idea of using a strictly-formatted function for reading potentially interactive input is rather questionable.
The problems with scanf are (at a minimum):
- using
%s
to get a string from the user, which leads to the possibility that the string may be longer than your buffer, causing overflow. - the possibility of a failed scan leaving your file pointer in an indeterminate location.
I very much prefer using fgets
to read whole lines in so that you can limit the amount of data read. If you've got a 1K buffer, and you read a line into it with fgets
you can tell if the line was too long by the fact there's no terminating newline character (last line of a file without a newline notwithstanding).
Then you can complain to the user, or allocate more space for the rest of the line (continuously if necessary until you have enough space). In either case, there's no risk of buffer overflow.
Once you've read the line in, you know that you're positioned at the next line so there's no problem there. You can then sscanf
your string to your heart's content without having to save and restore the file pointer for re-reading.
Here's a snippet of code which I frequently use to ensure no buffer overflow when asking the user for information.
It could be easily adjusted to use a file other than standard input if necessary and you could also have it allocate its own buffer (and keep increasing it until it's big enough) before giving that back to the caller (although the caller would then be responsible for freeing it, of course).
#include <stdio.h>
#include <string.h>
#define OK 0
#define NO_INPUT 1
#define TOO_LONG 2
#define SMALL_BUFF 3
static int getLine (char *prmpt, char *buff, size_t sz) {
int ch, extra;
// Size zero or one cannot store enough, so don't even
// try - we need space for at least newline and terminator.
if (sz < 2)
return SMALL_BUFF;
// Output prompt.
if (prmpt != NULL) {
printf ("%s", prmpt);
fflush (stdout);
}
// Get line with buffer overrun protection.
if (fgets (buff, sz, stdin) == NULL)
return NO_INPUT;
// Catch possibility of `\0` in the input stream.
size_t len = strlen(buff);
if (len < 1)
return NO_INPUT;
// If it was too long, there'll be no newline. In that case, we flush
// to end of line so that excess doesn't affect the next call.
if (buff[len - 1] != '\n') {
extra = 0;
while (((ch = getchar()) != '\n') && (ch != EOF))
extra = 1;
return (extra == 1) ? TOO_LONG : OK;
}
// Otherwise remove newline and give string back to caller.
buff[len - 1] = '\0';
return OK;
}
And, a test driver for it:
// Test program for getLine().
int main (void) {
int rc;
char buff[10];
rc = getLine ("Enter string> ", buff, sizeof(buff));
if (rc == NO_INPUT) {
// Extra NL since my system doesn't output that on EOF.
printf ("\nNo input\n");
return 1;
}
if (rc == TOO_LONG) {
printf ("Input too long [%s]\n", buff);
return 1;
}
printf ("OK [%s]\n", buff);
return 0;
}
Finally, a test run to show it in action:
$ printf "\0" | ./tstprg # Singular NUL in input stream.
Enter string>
No input
$ ./tstprg < /dev/null # EOF in input stream.
Enter string>
No input
$ ./tstprg # A one-character string.
Enter string> a
OK [a]
$ ./tstprg # Longer string but still able to fit.
Enter string> hello
OK [hello]
$ ./tstprg # Too long for buffer.
Enter string> hello there
Input too long [hello the]
$ ./tstprg # Test limit of buffer.
Enter string> 123456789
OK [123456789]
$ ./tstprg # Test just over limit.
Enter string> 1234567890
Input too long [123456789]
From the comp.lang.c FAQ: Why does everyone say not to use scanf? What should I use instead?
scanf
has a number of problems—see questions 12.17, 12.18a, and 12.19. Also, its%s
format has the same problem thatgets()
has (see question 12.23)—it’s hard to guarantee that the receiving buffer won’t overflow. [footnote]More generally,
scanf
is designed for relatively structured, formatted input (its name is in fact derived from “scan formatted”). If you pay attention, it will tell you whether it succeeded or failed, but it can tell you only approximately where it failed, and not at all how or why. You have very little opportunity to do any error recovery.Yet interactive user input is the least structured input there is. A well-designed user interface will allow for the possibility of the user typing just about anything—not just letters or punctuation when digits were expected, but also more or fewer characters than were expected, or no characters at all (i.e., just the RETURN key), or premature EOF, or anything. It’s nearly impossible to deal gracefully with all of these potential problems when using
scanf
; it’s far easier to read entire lines (withfgets
or the like), then interpret them, either usingsscanf
or some other techniques. (Functions likestrtol
,strtok
, andatoi
are often useful; see also questions 12.16 and 13.6.) If you do use anyscanf
variant, be sure to check the return value to make sure that the expected number of items were found. Also, if you use%s
, be sure to guard against buffer overflow.Note, by the way, that criticisms of
scanf
are not necessarily indictments offscanf
andsscanf
.scanf
reads fromstdin
, which is usually an interactive keyboard and is therefore the least constrained, leading to the most problems. When a data file has a known format, on the other hand, it may be appropriate to read it withfscanf
. It’s perfectly appropriate to parse strings withsscanf
(as long as the return value is checked), because it’s so easy to regain control, restart the scan, discard the input if it didn’t match, etc.Additional links:
- longer explanation by Chris Torek
- longer explanation by yours truly
References: K&R2 Sec. 7.4 p. 159
It is very hard to get scanf
to do the thing you want. Sure, you can, but things like scanf("%s", buf);
are as dangerous as gets(buf);
, as everyone has said.
As an example, what paxdiablo is doing in his function to read can be done with something like:
scanf("%10[^\n]%*[^\n]", buf));
getchar();
The above will read a line, store the first 10 non-newline characters in buf
, and then discard everything till (and including) a newline. So, paxdiablo's function could be written using scanf
the following way:
#include <stdio.h>
enum read_status {
OK,
NO_INPUT,
TOO_LONG
};
static int get_line(const char *prompt, char *buf, size_t sz)
{
char fmt[40];
int i;
int nscanned;
printf("%s", prompt);
fflush(stdout);
sprintf(fmt, "%%%zu[^\n]%%*[^\n]%%n", sz-1);
/* read at most sz-1 characters on, discarding the rest */
i = scanf(fmt, buf, &nscanned);
if (i > 0) {
getchar();
if (nscanned >= sz) {
return TOO_LONG;
} else {
return OK;
}
} else {
return NO_INPUT;
}
}
int main(void)
{
char buf[10+1];
int rc;
while ((rc = get_line("Enter string> ", buf, sizeof buf)) != NO_INPUT) {
if (rc == TOO_LONG) {
printf("Input too long: ");
}
printf("->%s<-\n", buf);
}
return 0;
}
One of the other problems with scanf
is its behavior in case of overflow. For example, when reading an int
:
int i;
scanf("%d", &i);
the above cannot be used safely in case of an overflow. Even for the first case, reading a string is much more simpler to do with fgets
rather than with scanf
.
Yes, you are right. There is a major security flaw in scanf
family(scanf
,sscanf
, fscanf
..etc) esp when reading a string, because they don't take the length of the buffer (into which they are reading) into account.
Example:
char buf[3];
sscanf("abcdef","%s",buf);
clearly the the buffer buf
can hold MAX 3
char. But the sscanf
will try to put "abcdef"
into it causing buffer overflow.
Problems I have with the *scanf()
family:
- Potential for buffer overflow with %s and %[ conversion specifiers. Yes, you can specify a maximum field width, but unlike with
printf()
, you can't make it an argument in thescanf()
call; it must be hardcoded in the conversion specifier. - Potential for arithmetic overflow with %d, %i, etc.
- Limited ability to detect and reject badly formed input. For example, "12w4" is not a valid integer, but
scanf("%d", &value);
will successfully convert and assign 12 tovalue
, leaving the "w4" stuck in the input stream to foul up a future read. Ideally the entire input string should be rejected, butscanf()
doesn't give you an easy mechanism to do that.
If you know your input is always going to be well-formed with fixed-length strings and numerical values that don't flirt with overflow, then scanf()
is a great tool. If you're dealing with interactive input or input that isn't guaranteed to be well-formed, then use something else.
Many answers here discuss the potential overflow issues of using scanf("%s", buf)
, but the latest POSIX specification more-or-less resolves this issue by providing an m
assignment-allocation character that can be used in format specifiers for c
, s
, and [
formats. This will allow scanf
to allocate as much memory as necessary with malloc
(so it must be freed later with free
).
An example of its use:
char *buf;
scanf("%ms", &buf); // with 'm', scanf expects a pointer to pointer to char.
// use buf
free(buf);
See here. Disadvantages to this approach is that it is a relatively recent addition to the POSIX specification and it is not specified in the C specification at all, so it remains rather unportable for now.
The advantage of scanf
is once you learn how use the tool, as you should always do in C, it has immensely useful usecases. You can learn how to use scanf
and friends by reading and understanding the manual. If you can't get through that manual without serious comprehension issues, this would probably indicate that you don't know C very well.
scanf
and friends suffered from unfortunate design choices that rendered it difficult (and occasionally impossible) to use correctly without reading the documentation, as other answers have shown. This occurs throughout C, unfortunately, so if I were to advise against using scanf
then I would probably advise against using C.
One of the biggest disadvantages seems to be purely the reputation it's earned amongst the uninitiated; as with many useful features of C we should be well informed before we use it. The key is to realise that as with the rest of C, it seems succinct and idiomatic, but that can be subtly misleading. This is pervasive in C; it's easy for beginners to write code that they think makes sense and might even work for them initially, but doesn't make sense and can fail catastrophically.
For example, the uninitiated commonly expect that the %s
delegate would cause a line to be read, and while that might seem intuitive it isn't necessarily true. It's more appropriate to describe the field read as a word. Reading the manual is strongly advised for every function.
What would any response to this question be without mentioning its lack of safety and risk of buffer overflows? As we've already covered, C isn't a safe language, and will allow us to cut corners, possibly to apply an optimisation at the expense of correctness or more likely because we're lazy programmers. Thus, when we know the system will never receive a string larger than a fixed number of bytes, we're given the ability to declare an array that size and forego bounds checking. I don't really see this as a down-fall; it's an option. Again, reading the manual is strongly advised and would reveal this option to us.
Lazy programmers aren't the only ones stung by scanf
. It's not uncommon to see people trying to read float
or double
values using %d
, for example. They're usually mistaken in believing that the implementation will perform some kind of conversion behind the scenes, which would make sense because similar conversions happen throughout the rest of the language, but that's not the case here. As I said earlier, scanf
and friends (and indeed the rest of C) are deceptive; they seem succinct and idiomatic but they aren't.
Inexperienced programmers aren't forced to consider the success of the operation. Suppose the user enters something entirely non-numeric when we've told scanf
to read and convert a sequence of decimal digits using %d
. The only way we can intercept such erroneous data is to check the return value, and how often do we bother checking the return value?
Much like fgets
, when scanf
and friends fail to read what they're told to read, the stream will be left in an unusual state;
- In the case of
fgets
, if there isn't sufficient space to store a complete line, then the remainder of the line left unread might be erroneously treated as though it's a new line when it isn't. - In the case of
scanf
and friends, a conversion failed as documented above, the erroneous data is left unread on the stream and might be erroneously treated as though it's part of a different field.
It's no easier to use scanf
and friends than to use fgets
. If we check for success by looking for a '\n'
when we're using fgets
or by inspecting the return value when we use scanf
and friends, and we find that we've read an incomplete line using fgets
or failed to read a field using scanf
, then we're faced with the same reality: We're likely to discard input (usually up until and including the next newline)! Yuuuuuuck!
Unfortunately, scanf
both simultaneously makes it hard (non-intuitive) and easy (fewest keystrokes) to discard input in this way. Faced with this reality of discarding user input, some have tried , not realising that the scanf("%*[^\n]%*c");
%*[^\n]
delegate will fail when it encounters nothing but a newline, and hence the newline will still be left on the stream.
A slight adaptation, by separating the two format delegates and we see some success here: scanf("%*[^\n]"); getchar();
. Try doing that with so few keystrokes using some other tool ;)
There is one big problem with scanf
-like functions - the lack of any type safety. That is, you can code this:
int i;
scanf("%10s", &i);
Hell, even this is "fine":
scanf("%10s", i);
It's worse than printf
-like functions, because scanf
expects a pointer, so crashes are more likely.
Sure, there are some format-specifier checkers out there, but, those are not perfect and well, they are not part of the language or the standard library.
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