I'm trying to create a simple function which returns me a date with a certain number of subtracted days from now, so something like this but I dont know the date classes well:
<?
function get_offset_hours ($hours) {
return date ("Y-m-d H:i:s", strtotime (date ("Y-m-d H:i:s") /*and now?*/));
}
function get_offset_days ($days) {
return date ("Y-m-d H:i:s", strtotime (date ("Y-m-d H:i:s") /*and now开发者_如何学Go?*/));
}
function get_offset_months ($months) {
return date ("Y-m-d H:i:s", strtotime (date ("Y-m-d H:i:s") /*and now?*/));
}
function get_offset_years ($years) {
return date ("Y-m-d H:i:s", strtotime (date ("Y-m-d H:i:s") + $years));
}
print get_offset_years (-30);
?>
Is it possible to do something similar to this? this kind of function works for years, but how to do the same with other time types?
For hours:
function get_offset_hours($hours)
{
return date('Y-m-d H:i:s', time() + 3600 * $hours);
}
Something like that will work well for hours and days (use 86400 for days), but for months and year it's a bit trickier...
Also you can also do it this way:
$date = strtotime(date('Y-m-d H:i:s') . ' +1 day');
$date = strtotime(date('Y-m-d H:i:s') . ' +1 week');
$date = strtotime(date('Y-m-d H:i:s') . ' +2 weeks');
$date = strtotime(date('Y-m-d H:i:s') . ' +1 month');
$date = strtotime(date('Y-m-d H:i:s') . ' +30 days');
$date = strtotime(date('Y-m-d H:i:s') . ' +1 year');
echo(date('Y-m-d H:i:s', $date));
Try to use datetime::sub
Example from the docs (linked):
<?php
$date = new DateTime("18-July-2008 16:30:30");
echo $date->format("d-m-Y H:i:s").'<br />';
date_sub($date, new DateInterval("P5D"));
echo '<br />'.$date->format("d-m-Y").' : 5 Days';
date_sub($date, new DateInterval("P5Y5M5D"));
echo '<br />'.$date->format("d-m-Y").' : 5 Days, 5 Months, 5 Years';
date_sub($date, new DateInterval("P5YT5H"));
echo '<br />'.$date->format("d-m-Y H:i:s").' : 5 Years, 5 Hours';
?>
something like this:
function offset hours($hours) {
return strtotime("+$hours hours");
}
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