I have a URL string in the following format.
http://myserver.com/_layouts/feed.aspx?xsl=4&web=%2F&page=dda3fd10-c776-4d69-8c55-2f1c74b343e2&wp=476f174a-82df-4611-a3df-e13255d97533
I want to replace &
with &
in the above URL. My result should be:
http://myserver.com/_layouts/feed.aspx?xsl=4&web=%2F&page=dda3fd10-c776-4d69-8c55-2f1c74b343e2&wp=476f174a-82df-4611-a3df-e13255d97533
Can someone post me the code to get this done?
i changed the 开发者_如何转开发code like this. but not working
if (name.equalsIgnoreCase(LINK))
{
Log.v(TAG,"link link: "+property.getFirstChild().getNodeValue().replace("&","&"));
message.setLink(property.getFirstChild().getNodeValue().replace("&","&"));
}
Thanks
How about:
private String decode(String url)
{
return url.replace("&", "&");
}
Decode:
Html.fromHtml((String) htmlCode).toString();
Encode:
TextUtils.htmlEncode(url)
String.replace(target, replacement)
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