Obviously when you're creating an actual string literal yourself, you backslash escape the double quote characters yourself.
var foo = "baz\"bat";
Just as you would with the handful of other control characters, like linebreaks and backslashes.
var bar = "baz\\bat\nmynew line and a \"quote\" ";
but if you're just wrapping that existing variable in quote character, ie to give it to some other system that requ开发者_高级运维ires quoted input, there's some confusion.
Obviously you have to escape any potential double quote characters that are in the string.
var doubleQuoteRe = /\"/g;
var quoted = "\"" + unquoted.replace(escaper, '\\\"') + "\"";
But according to some you also now have to worry about escaping literal backslash characters in the variable. In other words using much bigger hammer than my little regex. However i dont see why.
You might want to avoid escaping quotes you already escaped-
String.prototype.inquotes=function(){
return '"'+this.replace(/(^|[^\\])"/g,'$1\\"')+'"';
}
The answer is that yes, you have to do two things:
- replace literal backslash characters in the string, with two backslashes,
- THEN, you proceed replacing any occurrences of " with \".
the simplest explanation for why step 1 is essential, is to consider the 5-character string :
foo\"
After the first 3 characters (foo), there is a literal backslash character in the string, and then there is a literal double quote character.
(Put another way, as a string literal this would look like "foo\"")
If I were to only replace the quote character, i'd end up with a quoted string whose value was
foo\\"
But the two backslashes here will be interpreted as a single backslash. So when I wrap this value in quotes, I end up with unbalanced quotes.
"foo\\""
on the other hand, if I do step 1 first -- replacing all backslashes with double backslashes gives
foo\\"
and then step 2 -- replacing the quote with slash-quote gives
foo\\\"
Now when i wrap my value in quote characters i finally get
"foo\\\""
which is correct.
There is a non standard str.quote() in FF
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/quote They suggest the following polyfill
if(!String.prototype.quote){
// oop version - no dependencies
String.prototype.quote = (function(){
// prepare fallback
// ----------------
// backslash escape double quotes and backslashes
var escp_regex = /[\\"]/g,
escp_callback = '\\$&',
// escape control characters
ctrl_map = {
'\b': '\\b', // backspace
'\t': '\\t', // tab
'\n': '\\n', // new line
'\f': '\\f', // form feed
'\r': '\\r' // carriage return
},
// don't rely on `Object.keys(ctrl_map).join('')`
ctrl_regex = new RegExp('[\b\t\n\f\r]', 'g'),
ctrl_callback = function(match){
return ctrl_map[match];
},
// hex-escape, spare out control characters and ASCII printables
// [0-7,11,14-31,127-255]
xhex_regex = /[\x00-\x07\x0B\x0E-\x1F\x7F-\xFF]/g,
xhex_callback = function(match, char_code){
char_code = match.charCodeAt(0);
return '\\x' + (char_code < 16 ? '0' : '') + char_code;
},
// hex-escape all others
uhex_regex = /[\u0100-\uFFFF]/g,
uhex_callback = function(match, char_code){
char_code = match.charCodeAt(0);
return '\\u' + (char_code < 4096 ? '0' : '') + char_code;
},
// delegate to native `JSON.stringify` if available
stringify = typeof JSON !== 'undefined' && JSON.stringify;
// return actual polyfill
// ----------------------
return function(){
var self = this; // promote compression
if(self == null) throw new TypeError('can\'t convert ' + self + ' to object');
if(stringify) return stringify(self);
return '"' + self
.replace(escp_regex, escp_callback)
.replace(ctrl_regex, ctrl_callback)
.replace(xhex_regex, xhex_callback)
.replace(uhex_regex, uhex_callback) + '"';
}
}());
// generic version - requires Function#bind
String.quote = Function.call.bind(''.quote);
}
You might want to escape other characters aside from quotes, eg whitespace characters (newlines!) and/or non-ASCII characters. There's Crockford's quote()
, and my own implementation can be found at mercurial.intuxication.org.
精彩评论