Does anyone know a good way to test if one element, stored in a var, is the descendant of another, also stored in a var?
I don't need element1.isChildOf('selector')
, that's easy开发者_Go百科.
element1.isChildOf(element2)
element2.find(element1).size() > 0
Does not seem to work.
I don't want to have to write a plugin the uses .each
to test each child if I can avoid it.
If you're using 1.4, and are looking for a descendant rather than a child as your find()
example implies, there's a has()
method:
element2.has(element1).length > 0
You can use index()
for this. It will return -1 if an element isn't in the set. Assuming element1
and element2
are DOM elements and not jQuery objects:
if ($(element2).children().index(element1) != -1) {
// it's a child
}
For completeness, to test if something is a descendant and not just a child, it can also be used for that too:
if ($(element1).parents().index(element2) != -1) {
// element1 is a descendant of element2
}
As of Jquery 1.6 you can determine whether a jquery object is a child of another jquery object this way:
element2.is(element1.children());
Also notable, since is()
now accepts several different arguments (the first argument can be a function, jQuery selector, or DOM element), you can't think of the it simply as "is" anymore, but rather "is or is in".
I know this thread is old but this also works if you want to check upwards not downwards:
function isElementChildOf(childElement, parentElement) {
return 0 !== $(childElement).parents(parentElement).length;
}
Here is a working example
This is true
if element1 is the child of element2, in other words element1 has a parent, that is element2
$(element1).parents(element2).length
this way it is not OK, if the parent has more children (let say they are input
's):
$(element2).children(element1).length
精彩评论