MATLAB matrix replacement assignment gives error

I tried to update some part of a matrix, I got the following error message:

??? Assignment has fewer non-singleton rhs dimensions than non-singleton subscripts

My code tries to update some values of a matrix that represent a binary image. My code is as follows:

outImage(3:5,2:4,1) = max(imBinary(3:5,2:4,1));

When I delete last parameter (1), this time I get the same error. I guess there is a mismatch bet开发者_如何学运维ween dimensions but I could not get it. outImage is a new object that is created at that time (I tried to create it before, but nothing changed). What may be wrong?

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You mention in one of your comments on another answer that you are trying to create your own dilation algorithm, and therefore want to take the maximum value in a 3-by-3-by-1 submatrix and replace the values in that submatrix with the maximum value. The function MAX will by default operate along the columns of your submatrix, which will give you a 1-by-3 matrix (i.e. the maximum values of the columns of your 3-by-3-by-1 matrix). The error results because MATLAB can't assign a 1-by-3 matrix to a 3-by-3-by-1 matrix.

One solution is to call MAX again on your 1-by-3 matrix to get a scalar value, which you can then assign to each element of your 3-by-3-by-1 submatrix without error:

outImage(3:5,2:4,1) = max(max(imBinary(3:5,2:4,1)));

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On the rhs of your equation you take the max of a 3x3x1 sub-matrix, which returns a 1x3 vector. You then try to assign this to a 3x3x1 sub-matrix. A singleton subscript is one with the value 1. So the rhs has 1 non-singleton subscript, and the lhs has 2. Matlab can't figure out how to expand a 1x3 matrix to fill a 3x3x1 space.

I'm not entirely sure what you want to do, so I won't guess a solution. Do you want to make 3 copies of the rhs and put one into each row of the sub-matrix on the lhs ? Or are you trying to construct a 3x3x1 matrix on the rhs ?

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Do you want to fill all indexed elements in outImage by maximum value for each column of rhs expression? You can expand the row you get on rhs with REPMAT:

outImage(3:5,2:4,1) = repmat(max(imBinary(3:5,2:4,1)),3,1)

outImage(3:5,2:4) works as well.

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I got the same error before, and what I have done was defining the left hand matrix before. I don't know if you have the same case but you can try the following:

outImage=Zeros(M,N,K);

M, N, and K are the dimensions that you have. Then just type:

outImage(3:5,2:4,1) = max(max(imBinary(3:5,2:4,1)));