I have a list of hex bytes strings like this
['BB', 'A7', 'F6', '9E'] (as read from a text file)
How do I convert that list开发者_Go百科 to this format?
[0xBB, 0xA7, 0xF6, 0x9E]
[int(x, 16) for x in L]
[0xBB, 0xA7, 0xF6, 0x9E]
is the same as [187, 167, 158]
. So there's no special 'hex integer' form or the like.
But you can convert your hex strings to ints:
>>> [int(x, 16) for x in ['BB', 'A7', 'F6', '9E']]
[187, 167, 246, 158]
See also Convert hex string to int in Python
Depending on the format in the text file, it may be easier to convert directly
>>> b=bytearray('BBA7F69E'.decode('hex'))
or
>>> b=bytearray('BB A7 F6 9E'.replace(' ','').decode('hex'))
>>> b
bytearray(b'\xbb\xa7\xf6\x9e')
>>> b[0]
187
>>> hex(b[0])
'0xbb'
>>>
a bytearray is easily converted to a list
>>> list(b) == [0xBB, 0xA7, 0xF6, 0x9E]
True
>>> list(b)
[187, 167, 246, 158]
If you want to change the way the list is displayed you'll need to make your own list class
>>> class MyList(list):
... def __repr__(self):
... return '['+', '.join("0x%X"%x if type(x) is int else repr(x) for x in self)+']'
...
>>> MyList(b)
[0xBB, 0xA7, 0xF6, 0x9E]
>>> str(MyList(b))
'[0xBB, 0xA7, 0xF6, 0x9E]'
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