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How can I mix command line arguments and filenames for <> in Perl?

开发者 https://www.devze.com 2022-12-21 15:23 出处:网络
Consider the following silly Perl program: $firstarg = $ARGV[0]; print $firstarg; $input = <>; print $input;

Consider the following silly Perl program:

$firstarg = $ARGV[0];

print $firstarg;

$input = <>;

print $input;

I run it from a terminal开发者_JAVA百科 like:

perl myprog.pl sample_argument

And get this error:

Can't open sample_argument: No such file or directory at myprog.pl line 5.

Any ideas why this is? When it gets to the <> is it trying to read from the (non-existent) file, "sample_argument" or something? And why?


<> is shorthand for "read from the files specified in @ARGV, or if @ARGV is empty, then read from STDIN". In your program, @ARGV contains the value ("sample_argument"), and so Perl tries to read from that file when you use the <> operator.

You can fix it by clearing @ARGV before you get to the <> line:

$firstarg = shift @ARGV;
print $firstarg;
$input = <>;       # now @ARGV is empty, so read from STDIN
print $input;


See the perlio man page, which reads in part:

The null filehandle <> is special: it can be used to emulate the behavior of sed and awk. Input from <> comes either from standard input, or from each file listed on the command line. Here’s how it works: the first time <> is evaluated, the @ARGV array is checked, and if it is empty, $ARGV[0] is set to "-", which when opened gives you standard input. The @ARGV array is then processed as a list of filenames.

If you want STDIN, use STDIN, not <>.


By default, perl consumes the command line arguments as input files for <>. After you've used them, you should consume them yourself with shift;

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