std::开发者_运维问答ostringstream parmStream;
char parmName[1024];
THTTPUrl::Encode(parmName, pParm->Name().c_str(), 1024);
//I want to add the value of the paramName to the parmStream worked b4 when parmName was a string but obv not now
parmStream << "&" << parmName + "=";
Gives me the following .. error: invalid operands of types \u2018char [1024]\u2019 and \u2018const char [2]\u2019 to binary \u2018operator+\u2019
Cheers for the help in advance
Try
parmStream << "&" << parmName << "=";
I haven't check your code but it looks like the error is pointing to the fact you are trying to add the "=" to a standard C string.
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