I'm trying to change the name of a variable that is included inside a for loop and function call. In the example below, I'd like column_1 to be passed to the plot function, then column_2 etc. I've tried using do.call, but it returns "object 'column_j' not found". But object column_j is there, and the plot function works if I hard-code t开发者_如何学编程hem in. Help much appreciated.
for (j in 2:12) {
column_to_plot = paste("column_", j, sep = "")
do.call("plot", list(x, as.name(column_to_plot)))
}
I do:
x <- runif(100)
column_2 <-
column_3 <-
column_4 <-
column_5 <-
column_6 <-
column_7 <-
column_8 <-
column_9 <-
column_10 <-
column_11 <-
column_12 <- rnorm(100)
for (j in 2:12) {
column_to_plot = paste("column_", j, sep = "")
do.call("plot", list(x, as.name(column_to_plot)))
}
And I have no errors. Maybe you could provide hard-code which (according to your question) works, then will be simpler to find a reason of the error.
(I know that I can generate vectors using loop and assign
, but I want to provide clear example)
You can do it without the paste()
command in your for
loop. Simply assign the columns via the function colnames()
in your loop:
column_to_plot <- colnames(dataframeNAME)[j]
Hope that helps as a first kludge.
Are you trying to retrieve an object in the workspace by a character string? In that case, parse() might help:
for (j in 2:12) {
column_to_plot = paste("column_", j, sep = "")
plot(x, eval(parse(text=column_to_plot)))
}
In this case you could use do.call(), but it would not be required.
Edit: wrapp parse() in eval()
Here is one way to do it:
tmp.df <- data.frame(col_1=rnorm(10),col_2=rnorm(10),col_3=rnorm(10))
x <- seq(2,20,by=2)
plot(x, tmp.df$col_1)
for(j in 2:3){
name.list <- list("x",paste("col_",j,sep=""))
with(tmp.df, do.call("lines",lapply(name.list,as.name))) }
You can also do colnames(tmp.df)[j] instead of paste(..) if you'd like.
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