Say I had something like:
# %superhash is some predefined hash with more than 0 keys;
%hash = ();
foreach my $key (keys %superhash){
$superhash{ $key } = %hash;
%hash = ();
}
Would all the keys of superhash point to the same empty hash accessed by %hash
or would they be different empt开发者_运维技巧y hashes?
If not, how can I make sure they point to empty hashes?
You need to use the \
operator to take a reference to a plural data type (array or hash) before you can store it into a single slot of either. But in the example code given, if referenced, each would be the same hash.
The way to initialize your data structure is:
foreach my $key (keys %superhash) {
$superhash{ $key } = {}; # New empty hash reference
}
But initialization like this is largely unnecessary in Perl due to autovivification (creating appropriate container objects when a variable is used as a container).
my %hash;
$hash{a}{b} = 1;
Now %hash
has one key, 'a', which has a value of an anonymous hashref, containing the key/value pair b => 1
. Arrays autovivify in the same manner.
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