Given:
(def my-vec [{:a "foo" :b 10} {:a "bar" :b 13} {:a "baz" :b 7}])
How could iterate over each element to print that element's :a and the sum of all :b's to that point? That is:
"foo" 10
"bar" 23 "baz" 30I'm trying things like this to no avail:
; Does not work!
(map #(prn (:a %2) %1) (iterate #(+ (:b开发者_如何学C %2) %1) 0)) my-vec)
This doesn't work because the "iterate" lazy-seq can't refer to the current element in my-vec (as far as I can tell).
TIA! Sean
user> (reduce (fn [total {:keys [a b]}]
(let [total (+ total b)]
(prn a total)
total))
0 my-vec)
"foo" 10
"bar" 23
"baz" 30
30
You could look at this as starting with a sequence of maps, filtering out a sequence of the :a values and a separate sequence of the rolling sum of the :b values and then mapping a function of two arguments onto the two derived sequences.
create sequence of just the :a and :b values with
(map :a my-vec)
(map :b my-vec)
then a function to get the rolling sum:
(defn sums [sum seq]
"produce a seq of the rolling sum"
(if (empty? seq)
sum
(lazy-seq
(cons sum
(recur (+ sum (first seq)) (rest seq))))))
then put them together:
(map #(prn %1 %s) (map :a my-vec) (sums 0 (map :b my-vec)))
This separates the problem of generating the data from processing it. Hopefully this makes life easier.
PS: whats a better way of getting the rolling sum?
Transform it into the summed sequence:
(defn f [start mapvec]
(if (empty? mapvec) '()
(let [[ m & tail ] mapvec]
(cons [(m :a)(+ start (m :b))] (f (+ start (m :b)) tail)))))
Called as:
(f 0 my-vec)
returns:
(["foo" 10] ["bar" 23] ["baz" 30])
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