If I place atexit( fn );
on the exit stack, it will get executed when the program exits: returns from main()
or via exit()
.
Can I remove it from the stack?
Why do I want to do this, you ask?
I was experimenting with a simple try-catch mechanism using atexit
, setjmp
and longjmp
. It would be just perfect if I could undo-atexit(fn);
- even if it would only work for the last registered function.
Edit:
Following monoceres' suggestion to make my own stack...
The stack only works with one exception catcher for now.
void (*_catchFn[10])() = {0,0,0,0,0,0,0,0,0,0};
void _catch(){
if ( _catchFn[0] != 0 ){
(_catchFn[0])();
}
}
void _addCatch( void (*fn)() ){
_catchFn[0]=fn;
}
void _remCatch( void (*fn)() ){
_catchFn[0]=0;
}
void test(){
jmp_buf env;
void catch(){ // we get here after an exit with a r开发者_JS百科egistered catch
longjmp(env,1); // return to the line marked except...
// that first will get the value 1
}
int first = setjmp( env); // ** return here **
fprintf( stderr , "test: After setjmp. first=%d\n" , first );
if( first == 0 ){ // try this code
_addCatch(catch); // register the catch function to 'catch' the exit
fprintf( stderr , "test: Before CHECK\n" );
// CHECK something and something bad happens and it exits
exit(1); // like this
fprintf( stderr , "test: After CHECK - THIS SHOULD NEVER BE SEEN AFTER AN EXCEPTION.\n" );
}else{
fprintf( stderr , "test: After longjmp return. first=%d\n" , first );
}
_remCatch( catch);
fprintf( stderr , "test: IT WORKED!\n");
exit(1); // exit again to see if we are safe
}
int main(){
atexit( _catch ); // register my global exception stack
test();
}
Why not build your own stack that you call from a single atexit() function? That way you could manipulate the stack all you want.
No, you cannot do it, but you can use global flag so your exit handler will be doing nothing if the flag is set.
Alternatively you can call _Exit()
(C99) - it will perform normal exit procedure (close all open descriptors, send all needed signals and parent/children) but will not call exit handler.
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